Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Show that an infinite line of charge with linear charge density lamda exerts an attractive force on an electric dipole with magnitude F = (2)(Lamda)(p) / (4)(pie)(Epsilon knot)(r^2). Assume that r is much larger than the charge separation in the dipole.

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

http://web.mit.edu/6.013_book/www/chapter11/11.8.html
What part of this is the answer?
I don't understand what the answer is

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

start with the field of an infinite line of charge, what is that?
E= 1/(4pi€.) * ( 2(lambda))/r. Then what do I do?
differentiate and multiply by p :)
How would I differentiate? By dx?
did you look over the "force on a dipole" section?
Is the derivation clear?
r
Yes. I think. Lol
Do I differentiate or integrate?
differentiate that upside down triangle is the gradient (space derivative)
here everything only depends on r, no x's y's or z's needed to characterize the problem...
so the gradient is just the derivative with respect to r
Differintiating will get rid of r
nope. r is the variable.
what's the derivative of 1/r with respect to r?
\[-1/r ^{2}\]
Okay I got it. Is the final answer suppose to be negative?
all the rest of the terms are constants, they stay unchanged... multiply by the dipole moment (p) and you're done...
yes negative r hat is towards the center so it's an attractive force...
Oh now it makes sense thank you so much!! I may pass my quiz tomorrow now!
Hope it helped:) gl on the quiz!
Thanks

Not the answer you are looking for?

Search for more explanations.

Ask your own question