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haganmc
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Show that an infinite line of charge with linear charge density lamda exerts an attractive force on an electric dipole with magnitude F = (2)(Lamda)(p) / (4)(pie)(Epsilon knot)(r^2). Assume that r is much larger than the charge separation in the dipole.
 2 years ago
 2 years ago
haganmc Group Title
Show that an infinite line of charge with linear charge density lamda exerts an attractive force on an electric dipole with magnitude F = (2)(Lamda)(p) / (4)(pie)(Epsilon knot)(r^2). Assume that r is much larger than the charge separation in the dipole.
 2 years ago
 2 years ago

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Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
http://web.mit.edu/6.013_book/www/chapter11/11.8.html
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
What part of this is the answer?
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
I don't understand what the answer is
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
start with the field of an infinite line of charge, what is that?
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
E= 1/(4pi€.) * ( 2(lambda))/r. Then what do I do?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
differentiate and multiply by p :)
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
How would I differentiate? By dx?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
did you look over the "force on a dipole" section?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
Is the derivation clear?
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Yes. I think. Lol
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Do I differentiate or integrate?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
differentiate that upside down triangle is the gradient (space derivative)
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
here everything only depends on r, no x's y's or z's needed to characterize the problem...
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
so the gradient is just the derivative with respect to r
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Differintiating will get rid of r
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
nope. r is the variable.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
what's the derivative of 1/r with respect to r?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
\[1/r ^{2}\]
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Okay I got it. Is the final answer suppose to be negative?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
all the rest of the terms are constants, they stay unchanged... multiply by the dipole moment (p) and you're done...
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
yes negative r hat is towards the center so it's an attractive force...
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Oh now it makes sense thank you so much!! I may pass my quiz tomorrow now!
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
Hope it helped:) gl on the quiz!
 2 years ago
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