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haganmc
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Show that an infinite line of charge with linear charge density lamda exerts an attractive force on an electric dipole with magnitude F = (2)(Lamda)(p) / (4)(pie)(Epsilon knot)(r^2). Assume that r is much larger than the charge separation in the dipole.
 one year ago
 one year ago
haganmc Group Title
Show that an infinite line of charge with linear charge density lamda exerts an attractive force on an electric dipole with magnitude F = (2)(Lamda)(p) / (4)(pie)(Epsilon knot)(r^2). Assume that r is much larger than the charge separation in the dipole.
 one year ago
 one year ago

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Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
http://web.mit.edu/6.013_book/www/chapter11/11.8.html
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
What part of this is the answer?
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
I don't understand what the answer is
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
start with the field of an infinite line of charge, what is that?
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
E= 1/(4pi€.) * ( 2(lambda))/r. Then what do I do?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
differentiate and multiply by p :)
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
How would I differentiate? By dx?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
did you look over the "force on a dipole" section?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
Is the derivation clear?
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Yes. I think. Lol
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Do I differentiate or integrate?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
differentiate that upside down triangle is the gradient (space derivative)
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
here everything only depends on r, no x's y's or z's needed to characterize the problem...
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
so the gradient is just the derivative with respect to r
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Differintiating will get rid of r
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
nope. r is the variable.
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
what's the derivative of 1/r with respect to r?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
\[1/r ^{2}\]
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Okay I got it. Is the final answer suppose to be negative?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
all the rest of the terms are constants, they stay unchanged... multiply by the dipole moment (p) and you're done...
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
yes negative r hat is towards the center so it's an attractive force...
 one year ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
Oh now it makes sense thank you so much!! I may pass my quiz tomorrow now!
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
Hope it helped:) gl on the quiz!
 one year ago
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