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haganmc
 3 years ago
Show that an infinite line of charge with linear charge density lamda exerts an attractive force on an electric dipole with magnitude F = (2)(Lamda)(p) / (4)(pie)(Epsilon knot)(r^2). Assume that r is much larger than the charge separation in the dipole.
haganmc
 3 years ago
Show that an infinite line of charge with linear charge density lamda exerts an attractive force on an electric dipole with magnitude F = (2)(Lamda)(p) / (4)(pie)(Epsilon knot)(r^2). Assume that r is much larger than the charge separation in the dipole.

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haganmc
 3 years ago
Best ResponseYou've already chosen the best response.0What part of this is the answer?

haganmc
 3 years ago
Best ResponseYou've already chosen the best response.0I don't understand what the answer is

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1start with the field of an infinite line of charge, what is that?

haganmc
 3 years ago
Best ResponseYou've already chosen the best response.0E= 1/(4pi€.) * ( 2(lambda))/r. Then what do I do?

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1differentiate and multiply by p :)

haganmc
 3 years ago
Best ResponseYou've already chosen the best response.0How would I differentiate? By dx?

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1did you look over the "force on a dipole" section?

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1Is the derivation clear?

haganmc
 3 years ago
Best ResponseYou've already chosen the best response.0Do I differentiate or integrate?

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1differentiate that upside down triangle is the gradient (space derivative)

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1here everything only depends on r, no x's y's or z's needed to characterize the problem...

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1so the gradient is just the derivative with respect to r

haganmc
 3 years ago
Best ResponseYou've already chosen the best response.0Differintiating will get rid of r

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1nope. r is the variable.

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1what's the derivative of 1/r with respect to r?

haganmc
 3 years ago
Best ResponseYou've already chosen the best response.0Okay I got it. Is the final answer suppose to be negative?

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1all the rest of the terms are constants, they stay unchanged... multiply by the dipole moment (p) and you're done...

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1yes negative r hat is towards the center so it's an attractive force...

haganmc
 3 years ago
Best ResponseYou've already chosen the best response.0Oh now it makes sense thank you so much!! I may pass my quiz tomorrow now!

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1Hope it helped:) gl on the quiz!
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