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In solving the equation (x + 1)(x – 2) = 4, Eric stated that the solution would be
x + 1 = 4 => x = 3
or
(x – 2) = 4 => x = 6
However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning.
 one year ago
 one year ago
In solving the equation (x + 1)(x – 2) = 4, Eric stated that the solution would be x + 1 = 4 => x = 3 or (x – 2) = 4 => x = 6 However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning.
 one year ago
 one year ago

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HawkCrimsonBest ResponseYou've already chosen the best response.0
to put it simplly (x+1)(x2) must be equal to "0" not 4 for that method to work so that is y he is wrong
 one year ago

HawkCrimsonBest ResponseYou've already chosen the best response.0
what you must do is this (x+1)(x2)=4 x^2x2=4 x^2x6=0 (x+2)(x3)=0 therefore x=2 or x=3
 one year ago
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