SmartScore 99
SmartScore 86
SmartScore 92
Here's the question you clicked on:
Rebbbtx
solve for F: C=5/9(F-32)
9/5C+32
Divide by 5/9, then add 32 to both sides. \[C={5\over9}(F-32)\] \[{C \over {5 \over 9}}=F-32\] \[{9C \over 5}+32 = F\]
Not the answer you are looking for?Search for more explanations.