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mlbach Group Title

13x=7x+5

  • one year ago
  • one year ago

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  1. PhoenixFire Group Title
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    Solve for x?

    • one year ago
  2. mlbach Group Title
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    yes, i dont even know where to start!!!!

    • one year ago
  3. zzr0ck3r Group Title
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    subtract 7x from both sides and tell me what you got

    • one year ago
  4. rainbow22 Group Title
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    5/6

    • one year ago
  5. rainbow22 Group Title
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    =x

    • one year ago
  6. zzr0ck3r Group Title
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    @rainbow dont just give answers. Please read rules.

    • one year ago
  7. PhoenixFire Group Title
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    \[13x=7x+5\] Subtract 7x from both sides. \[13x-7x=7x-7x+5\] Combine like terms \[6x=5\] Divide both sides by 6 \[x={5 \over 6}\]

    • one year ago
  8. zzr0ck3r Group Title
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    we are not saposed to give them the answers, you should involve them in getting the answer...

    • one year ago
  9. PhoenixFire Group Title
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    Sorry @zzr0ck3r I'll remember for next time.

    • one year ago
  10. mlbach Group Title
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    AHHHHH..Thank you so much Phoenixfire for explaining!!!

    • one year ago
  11. mlbach Group Title
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    X-2/5=1/2

    • one year ago
  12. mlbach Group Title
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    how would i start this one?

    • one year ago
  13. PhoenixFire Group Title
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    Add 2/5 to both sides. What do you get?

    • one year ago
  14. mlbach Group Title
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    im horrible at this!!! add 2/5 to 2/5 and 1/2?

    • one year ago
  15. PhoenixFire Group Title
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    Yes. type out the entire equation with 2/5 added to both sides.

    • one year ago
  16. PhoenixFire Group Title
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    @mlbach Did you get it?

    • one year ago
  17. mlbach Group Title
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    no, im sorry, trying to do it on paper

    • one year ago
  18. mlbach Group Title
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    im 38 and math is like a foreign language to me!

    • one year ago
  19. PhoenixFire Group Title
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    You have \[x-{2 \over 5}={1 \over 2}\] So, add 2/5. You get: \[x-{2 \over 5}+{2 \over 5}={1 \over 2}+{2 \over 5}\] Try solve from there.

    • one year ago
  20. mlbach Group Title
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    x-4/5=9/10

    • one year ago
  21. mlbach Group Title
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    is that right...9/10

    • one year ago
  22. PhoenixFire Group Title
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    You can see that the -2/5+2/5 results in 0. \[x-0={1 \over 2}+{2 \over 5}\] But you got the right hand side correct.

    • one year ago
  23. mlbach Group Title
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    ok, they cancel each other out right?

    • one year ago
  24. PhoenixFire Group Title
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    Correct! So, \[x={9 \over 10}\]

    • one year ago
  25. mlbach Group Title
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    YAY!!!!! thank you!!!

    • one year ago
  26. PhoenixFire Group Title
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    No problem. :) Any other problems?

    • one year ago
  27. mlbach Group Title
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    2/7X=6

    • one year ago
  28. PhoenixFire Group Title
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    \[{2 \over 7}x=6\] Divide both sides by 2/7. The one the left will cancel and then you're left with x=??

    • one year ago
  29. mlbach Group Title
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    how do i know that im dividing?

    • one year ago
  30. PhoenixFire Group Title
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    \[{2 \over 7}x=6\] Divide by 2/7\[{{{2 \over 7}x} \over {2 \over 7}}={6 \over {2 \over 7}}\]

    • one year ago
  31. PhoenixFire Group Title
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    \[{{2 \over 7} \over {2 \over 7}}=1\] Do you understand that? Anything divided by itself is 1.

    • one year ago
  32. mlbach Group Title
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    yes

    • one year ago
  33. mlbach Group Title
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    i just dont know how to do 6 divided by 2/7

    • one year ago
  34. PhoenixFire Group Title
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    So, that leave \[1x={6 \over {2 \over 7}}\] Now, a trick is to dividing by fractions: \[{a \over {b \over c}}={{c \over b}a}\] You flip the bottom fraction and multiply the top by it. Giving you: \[{6 \over {2 \over 7}}={7 \over 2}6\] Or \[{7*6} \over 2\]

    • one year ago
  35. PhoenixFire Group Title
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    Sorry about the bad grammar.. That was truly horrible.

    • one year ago
  36. mlbach Group Title
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    21?

    • one year ago
  37. PhoenixFire Group Title
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    Yes! \[x=21\]

    • one year ago
  38. mlbach Group Title
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    can i just put you in my pocket and and take you to class with me?

    • one year ago
  39. PhoenixFire Group Title
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    Hahaha. Yes, if you have a cell phone and internet on it. :)

    • one year ago
  40. mlbach Group Title
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    lol

    • one year ago
  41. mlbach Group Title
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    A telephone book has white pages and yellow pages. ¾ of the book consists of the white pages; the yellow pages number 300. What is the total number of pages in the telephone book?

    • one year ago
  42. mlbach Group Title
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    how would i start this one

    • one year ago
  43. PhoenixFire Group Title
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    White=3/4 of the book Yellow=1/4 of the book. So, if 1/4 of the book is 300. How many total pages are there?

    • one year ago
  44. mlbach Group Title
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    900

    • one year ago
  45. PhoenixFire Group Title
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    Almost. Y=yellow=1/4=300 W=white=3/4=300*3 T=total=W+Y=(300*3)+300=1200

    • one year ago
  46. mlbach Group Title
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    ah. i got it

    • one year ago
  47. mlbach Group Title
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    A theater usher at a Broadway musical finds that ½ of the patrons attending a performance are in their seats by show time. The remaining 60 people are seated after the opening number. If the show is always a complete sellout, how many seats does the theater have?

    • one year ago
  48. PhoenixFire Group Title
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    This one is mostly a play on words. If you single out a few words: "1/2", "remaining", "sellout" From this you can see that "sellout" says all seats are taken. "remaining" means those not seated initially. "1/2" the initial people seated. So, if "half" of the attendees are seated before the show, and the "remaining" are seated after the first number. How many seats are there in the theater which is "sold out (ie all seats taken)"?

    • one year ago
  49. PhoenixFire Group Title
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    *** "remaining 60" ***

    • one year ago
  50. mlbach Group Title
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    120?

    • one year ago
  51. PhoenixFire Group Title
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    Correct!

    • one year ago
  52. mlbach Group Title
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    YAY!!!! lol

    • one year ago
  53. PhoenixFire Group Title
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    Getting the hang of it?

    • one year ago
  54. mlbach Group Title
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    right now i am, but come test time, I'll draw a blank!

    • one year ago
  55. mlbach Group Title
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    Of those invited to a wedding, 2/7 were friends of the bride. The friends of the groom numbered 65. How many people were invited to the wedding

    • one year ago
  56. PhoenixFire Group Title
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    Haha. Of course. Nobody can avoid the blank come test time.

    • one year ago
  57. mlbach Group Title
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    unfortunatley not!

    • one year ago
  58. mlbach Group Title
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    what do i look at first?

    • one year ago
  59. PhoenixFire Group Title
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    bride=2/7 Therefore, groom=5/7=65 You can take this known number as a percentile of the total attendees. \[{5 \over 7}T=65\] Where T= the total number of people attending. Now solve for T.

    • one year ago
  60. mlbach Group Title
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    where did you get 5/7 from?

    • one year ago
  61. PhoenixFire Group Title
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    Well if the brides guests are 2/7 of the attending people. then the grooms is the remaining guests. Correct? so 1-2/7 = 5/7

    • one year ago
  62. mlbach Group Title
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    oh ok

    • one year ago
  63. PhoenixFire Group Title
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    To solve for T you use the same method as one of the other problems above. The funny trick with dividing by fractions.

    • one year ago
  64. PhoenixFire Group Title
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    Got it yet?

    • one year ago
  65. mlbach Group Title
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    not quite

    • one year ago
  66. PhoenixFire Group Title
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    What are you stuck on?

    • one year ago
  67. mlbach Group Title
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    5/7T=65....i get stuck on how to work the problem out

    • one year ago
  68. PhoenixFire Group Title
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    Well you want to isolate T. Because that's the unknown variable that you want to become known. So in this case, the only way to do that is to remove the 5/7 from T. You will want to divide by 5/7 to make it cancel out, leaving T alone on the left.

    • one year ago
  69. mlbach Group Title
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    so do i divide both sidesby 5/7?

    • one year ago
  70. mlbach Group Title
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    answer is 91?

    • one year ago
  71. PhoenixFire Group Title
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    Yes. Because if you change the equation on the left, you have to change it in the same way on the right for the equality to hold. 91 is correct!

    • one year ago
  72. mlbach Group Title
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    awesome!!!!

    • one year ago
  73. mlbach Group Title
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    thank you so much for your help, I appreciate it!

    • one year ago
  74. PhoenixFire Group Title
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    No problem at all. Become a fan of me, and if you need help just send me a message.

    • one year ago
  75. mlbach Group Title
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    Done!

    • one year ago
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