Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
across
Group Title
Whilst studying the heat equation, I ran into the equality\[e(x,t)=c(x)\rho(x)u(x,t),\]where \(e\) is the thermal energy density, \(c\) is the specific heat, \(\rho\) is the mass density, and \(u\) is the temperature.
Why is this true, who came up with it, and how?
 2 years ago
 2 years ago
across Group Title
Whilst studying the heat equation, I ran into the equality\[e(x,t)=c(x)\rho(x)u(x,t),\]where \(e\) is the thermal energy density, \(c\) is the specific heat, \(\rho\) is the mass density, and \(u\) is the temperature. Why is this true, who came up with it, and how?
 2 years ago
 2 years ago

This Question is Closed

Kainui Group TitleBest ResponseYou've already chosen the best response.0
Look at the units of each bit and do some dimensional analysis. What does your intuition say about multiplying the density of a metal times its volume for instance? Use this bit of logic to work your way through each bit of it and it'll start to clear up I think. =D
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
that comes from the definition of specific heat capacity ...
 2 years ago

Carl_Pham Group TitleBest ResponseYou've already chosen the best response.1
This looks like some kind of excess thermal energy density, something like the deviations from average as a function of time and space, as might describe the flow of a heat pulse through a solid material, for example. So let's say a little bit of the material at location x and time t was heated up by u degrees. What would be the extra energy required? Well, we have to multiply u by the mass in the region near x at time t and by the heat capacity of the material. That would tell us E = m c u. If we divide by the mass of the little region, so we get densities, then we have e(x,t) = p(x,t) c(x) u(x,t), where e is the energy density (energy per gram), p is the mass density (mass per gram), c is the heat capacity per gram (which apparently you are supposed to assume may vary with position, ,but not with time), and u is the temperature deviation.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
what's that ... heat transfer equation?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
\[ {\partial u \over \partial t}  k \nabla^2u =0 \] ??
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
not sure you would get the eqn asked by OP using heat transfer eqn ... i hate it. i might fail because of it.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
time and position dependent heat equation ... i thought that would only be for steady state. I have no idea on it's generalizations.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
forget it ... i had enough of PDE's
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.