• anonymous
calculate the radius of convergence and the interval of convergence (with examination of the endpoints) $\sum_{n=1}^{\infty}\frac{3^{n+1}}{n}.x^{n}$ a try... $|\frac{a_{n+1}}{a_{n}}|=$ $\Large \frac{\frac{3^{(n+1)+1}}{n+1}}{\frac{3^{n+1}}{n}}=$ $\frac{3^{n+2}}{n+1}.\frac{n}{3^{n+1}}=\frac{3}{1}=3$ is it correct and what i need to do additional?
Mathematics

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