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How does x/(x+1) = 1-1/(x+1)

Mathematics
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Do you know about LCM or LCD ???
you can split up the numerator \[\implies \frac{x+1 - 1}{x+1}\] now split up the fraction \[\implies \frac{x+1}{x+1} - \frac{1}{x+1}\] does that give you a hint?
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Other answers:

There are two methods for this: Solve RHS to get LHS.. And other is make some arrangements in LHS to get RHS..
First Method is shown by @chihiroasleaf and second method is shown by @lgbasallote
If you start with x/(x+1) how can you realize that it equals 1-1/(x+1)/
like i said \[\frac{x}{x+1} \implies \frac{x+1 - 1}{x+1} \implies \frac{x+1}{x+1} - \frac{1}{x+1} \implies 1- \frac 1{x+1}\]
That is what @lgbasallote has shown to you..
In the numerator if you add and subtract 1 then there is no effect on the equality...
Oh, so this is almost like multiple the numerator and denominator by x/x (for example).
yes!!`
except you do addition-subtraction
You got it..
thanks!
Welcome dear..

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