anonymous
  • anonymous
How does x/(x+1) = 1-1/(x+1)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Do you know about LCM or LCD ???
lgbasallote
  • lgbasallote
you can split up the numerator \[\implies \frac{x+1 - 1}{x+1}\] now split up the fraction \[\implies \frac{x+1}{x+1} - \frac{1}{x+1}\] does that give you a hint?
chihiroasleaf
  • chihiroasleaf
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anonymous
  • anonymous
There are two methods for this: Solve RHS to get LHS.. And other is make some arrangements in LHS to get RHS..
anonymous
  • anonymous
First Method is shown by @chihiroasleaf and second method is shown by @lgbasallote
anonymous
  • anonymous
If you start with x/(x+1) how can you realize that it equals 1-1/(x+1)/
lgbasallote
  • lgbasallote
like i said \[\frac{x}{x+1} \implies \frac{x+1 - 1}{x+1} \implies \frac{x+1}{x+1} - \frac{1}{x+1} \implies 1- \frac 1{x+1}\]
anonymous
  • anonymous
That is what @lgbasallote has shown to you..
anonymous
  • anonymous
In the numerator if you add and subtract 1 then there is no effect on the equality...
anonymous
  • anonymous
Oh, so this is almost like multiple the numerator and denominator by x/x (for example).
lgbasallote
  • lgbasallote
yes!!`
lgbasallote
  • lgbasallote
except you do addition-subtraction
anonymous
  • anonymous
You got it..
anonymous
  • anonymous
thanks!
anonymous
  • anonymous
Welcome dear..

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