## asdfasdfasdfasdfasdf1 3 years ago How does x/(x+1) = 1-1/(x+1)

1. waterineyes

Do you know about LCM or LCD ???

2. lgbasallote

you can split up the numerator $\implies \frac{x+1 - 1}{x+1}$ now split up the fraction $\implies \frac{x+1}{x+1} - \frac{1}{x+1}$ does that give you a hint?

3. chihiroasleaf

|dw:1346926618139:dw|

4. waterineyes

There are two methods for this: Solve RHS to get LHS.. And other is make some arrangements in LHS to get RHS..

5. waterineyes

First Method is shown by @chihiroasleaf and second method is shown by @lgbasallote

6. asdfasdfasdfasdfasdf1

If you start with x/(x+1) how can you realize that it equals 1-1/(x+1)/

7. lgbasallote

like i said $\frac{x}{x+1} \implies \frac{x+1 - 1}{x+1} \implies \frac{x+1}{x+1} - \frac{1}{x+1} \implies 1- \frac 1{x+1}$

8. waterineyes

That is what @lgbasallote has shown to you..

9. waterineyes

In the numerator if you add and subtract 1 then there is no effect on the equality...

10. asdfasdfasdfasdfasdf1

Oh, so this is almost like multiple the numerator and denominator by x/x (for example).

11. lgbasallote

yes!!`

12. lgbasallote

13. waterineyes

You got it..

14. asdfasdfasdfasdfasdf1

thanks!

15. waterineyes

Welcome dear..