## asdfasdfasdfasdfasdf1 Group Title How does x/(x+1) = 1-1/(x+1) 2 years ago 2 years ago

1. waterineyes Group Title

Do you know about LCM or LCD ???

2. lgbasallote Group Title

you can split up the numerator $\implies \frac{x+1 - 1}{x+1}$ now split up the fraction $\implies \frac{x+1}{x+1} - \frac{1}{x+1}$ does that give you a hint?

3. chihiroasleaf Group Title

|dw:1346926618139:dw|

4. waterineyes Group Title

There are two methods for this: Solve RHS to get LHS.. And other is make some arrangements in LHS to get RHS..

5. waterineyes Group Title

First Method is shown by @chihiroasleaf and second method is shown by @lgbasallote

6. asdfasdfasdfasdfasdf1 Group Title

If you start with x/(x+1) how can you realize that it equals 1-1/(x+1)/

7. lgbasallote Group Title

like i said $\frac{x}{x+1} \implies \frac{x+1 - 1}{x+1} \implies \frac{x+1}{x+1} - \frac{1}{x+1} \implies 1- \frac 1{x+1}$

8. waterineyes Group Title

That is what @lgbasallote has shown to you..

9. waterineyes Group Title

In the numerator if you add and subtract 1 then there is no effect on the equality...

10. asdfasdfasdfasdfasdf1 Group Title

Oh, so this is almost like multiple the numerator and denominator by x/x (for example).

11. lgbasallote Group Title

yes!!`

12. lgbasallote Group Title

13. waterineyes Group Title

You got it..

14. asdfasdfasdfasdfasdf1 Group Title

thanks!

15. waterineyes Group Title

Welcome dear..