## Mello 3 years ago Find all the whole number values of n, that would make the following statement true. (3n+9)/(n+1)

1. mayankdevnani

2. mayankdevnani

@Mello

3. Mello

Thanks, but there was a set of numbers on the example question. 0 works, what else?

4. mayankdevnani

(3n+9)/(n+1) it is wholly divided....

5. Mello

What do you mean by, wholly divided?

6. mayankdevnani

means the remainder is zero(0)

7. Mello

Right. But I'm pretty sure there are other values of n, that also leaves a remainder of 0

8. chihiroasleaf

n = 2 ?

9. mayankdevnani

no one whole no. can be fully satisfied with n

10. mayankdevnani

@Mello

11. mayankdevnani

there would be some integers..

12. chihiroasleaf

I think $n = 3k-1, k \in \mathbb{N}$

13. Mello

Oh I got it, 0; 1; 2; 5; -2; -3; -4; -7 Heh, thanks for your help :)

14. mayankdevnani

thanx for who??

15. mayankdevnani

@Mello

16. mayankdevnani

are you there??

17. chihiroasleaf

if n is whole number, so negative integers can't be the solution, since whole number starts at 0,1,2,3,....

18. mukushla

$\frac{3n+9}{n+1}=\frac{3n+3+6}{n+1}=3+\frac{6}{n+1}$so $$n+1|6$$ and we have$n+1=\pm1,\pm2,\pm3,\pm6$

19. chihiroasleaf

@mukushla are negative numbers also the solutions? since the question ask for n to be whole number

20. mukushla

u r right negatives are not solution

21. mukushla

only solutions are $$n=0,1,2,5$$

22. Mello

@mayankdevnani everyone who helped. @chihiroasleaf @mukushla Sorry, I translated this from another language. I think the correct term was integer. Thanks again to everyone for your input!

23. mukushla

np :)