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anonymous
 3 years ago
Find all the whole number values of n, that would make the following statement true. (3n+9)/(n+1)
anonymous
 3 years ago
Find all the whole number values of n, that would make the following statement true. (3n+9)/(n+1)

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mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0means answer should be 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks, but there was a set of numbers on the example question. 0 works, what else?

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0(3n+9)/(n+1) it is wholly divided....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you mean by, wholly divided?

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0means the remainder is zero(0)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Right. But I'm pretty sure there are other values of n, that also leaves a remainder of 0

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0no one whole no. can be fully satisfied with n

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0there would be some integers..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think \[n = 3k1, k \in \mathbb{N}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh I got it, 0; 1; 2; 5; 2; 3; 4; 7 Heh, thanks for your help :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if n is whole number, so negative integers can't be the solution, since whole number starts at 0,1,2,3,....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3n+9}{n+1}=\frac{3n+3+6}{n+1}=3+\frac{6}{n+1}\]so \(n+16\) and we have\[n+1=\pm1,\pm2,\pm3,\pm6\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mukushla are negative numbers also the solutions? since the question ask for n to be whole number

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u r right negatives are not solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0only solutions are \(n=0,1,2,5\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mayankdevnani everyone who helped. @chihiroasleaf @mukushla Sorry, I translated this from another language. I think the correct term was integer. Thanks again to everyone for your input!
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