Mello
Find all the whole number values of n, that would make the following statement true. (3n+9)/(n+1)
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mayankdevnani
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means answer should be 0
mayankdevnani
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@Mello
Mello
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Thanks, but there was a set of numbers on the example question. 0 works, what else?
mayankdevnani
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(3n+9)/(n+1) it is wholly divided....
Mello
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What do you mean by, wholly divided?
mayankdevnani
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means the remainder is zero(0)
Mello
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Right. But I'm pretty sure there are other values of n, that also leaves a remainder of 0
chihiroasleaf
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n = 2 ?
mayankdevnani
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no one whole no. can be fully satisfied with n
mayankdevnani
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@Mello
mayankdevnani
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there would be some integers..
chihiroasleaf
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I think \[n = 3k-1, k \in \mathbb{N}\]
Mello
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Oh I got it, 0; 1; 2; 5; -2; -3; -4; -7
Heh, thanks for your help :)
mayankdevnani
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thanx for who??
mayankdevnani
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@Mello
mayankdevnani
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are you there??
chihiroasleaf
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if n is whole number, so negative integers can't be the solution,
since whole number starts at 0,1,2,3,....
mukushla
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\[\frac{3n+9}{n+1}=\frac{3n+3+6}{n+1}=3+\frac{6}{n+1}\]so \(n+1|6\) and we have\[n+1=\pm1,\pm2,\pm3,\pm6\]
chihiroasleaf
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@mukushla are negative numbers also the solutions? since the question ask for n to be whole number
mukushla
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u r right negatives are not solution
mukushla
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only solutions are \(n=0,1,2,5\)
Mello
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@mayankdevnani everyone who helped.
@chihiroasleaf @mukushla Sorry, I translated this from another language. I think the correct term was integer.
Thanks again to everyone for your input!
mukushla
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np :)