## anonymous 3 years ago Find all the whole number values of n, that would make the following statement true. (3n+9)/(n+1)

1. mayankdevnani

2. mayankdevnani

@Mello

3. anonymous

Thanks, but there was a set of numbers on the example question. 0 works, what else?

4. mayankdevnani

(3n+9)/(n+1) it is wholly divided....

5. anonymous

What do you mean by, wholly divided?

6. mayankdevnani

means the remainder is zero(0)

7. anonymous

Right. But I'm pretty sure there are other values of n, that also leaves a remainder of 0

8. anonymous

n = 2 ?

9. mayankdevnani

no one whole no. can be fully satisfied with n

10. mayankdevnani

@Mello

11. mayankdevnani

there would be some integers..

12. anonymous

I think $n = 3k-1, k \in \mathbb{N}$

13. anonymous

Oh I got it, 0; 1; 2; 5; -2; -3; -4; -7 Heh, thanks for your help :)

14. mayankdevnani

thanx for who??

15. mayankdevnani

@Mello

16. mayankdevnani

are you there??

17. anonymous

if n is whole number, so negative integers can't be the solution, since whole number starts at 0,1,2,3,....

18. anonymous

$\frac{3n+9}{n+1}=\frac{3n+3+6}{n+1}=3+\frac{6}{n+1}$so $$n+1|6$$ and we have$n+1=\pm1,\pm2,\pm3,\pm6$

19. anonymous

@mukushla are negative numbers also the solutions? since the question ask for n to be whole number

20. anonymous

u r right negatives are not solution

21. anonymous

only solutions are $$n=0,1,2,5$$

22. anonymous

@mayankdevnani everyone who helped. @chihiroasleaf @mukushla Sorry, I translated this from another language. I think the correct term was integer. Thanks again to everyone for your input!

23. anonymous

np :)