A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
How do you know that tan(1/2) = pi/4 and tan(1/4) = 1.. etc. etc?
anonymous
 4 years ago
How do you know that tan(1/2) = pi/4 and tan(1/4) = 1.. etc. etc?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm tan (1/2) = pi/4?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my bad, tan(1) = pi/4. are there any tricks to remembering them? and I mean arctan!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ahh are you familiar with the 454590 triangle?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346929711704:dw so as you can see from my triangle... \[\tan (\frac \pi 4 ) = 1\] therefore.. \[\tan^{1} (1) = \frac \pi 4\] does that help?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes.. great :D is there a way to remember them for like cos/sin?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes. this is how you remember it. using triangles. sin and cosine are also from triangles

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just remember these two triangles dw:1346929906503:dw and dw:1346929946985:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A 0 pi/6 pi/4 pi/3 pi/2 SinA

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0First make table like that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so you can find out that \[\sin (\frac \pi 3) = \frac{opposite}{hypotenuse} = \frac {\sqrt 3} 2\] or\[\tan (\frac \pi 6) = \frac{opposite}{adjacent} = \frac{1}{\sqrt 3}\] and so on...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think that's what you meant? \[\tan = \frac{opposite}{hypotenuse} \frac{\sin}{\cos}\] @asdfasdfasdfasdfasdf1 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there should be equal sign there ^

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, A 0 pi/6 pi/4 pi/3 pi/2 SinA ( 0/4)^1/2 (1/4)^1/2 (2/4)^1/2 (3/4)^1/2 (4/4)^1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, once we know SinA we will know CosA too

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A 0 pi/6 pi/4 pi/3 pi/2 SinA ( 0/4)^1/2 (1/4)^1/2 (2/4)^1/2 (3/4)^1/2 (4/4)^1/2 CosA (4/4)^1/2 (3/4)^1/2 (2/4)^1/2 (1/4)^1/2 (0/4)^1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, Find Tan A by using formula Tan A = Sin A/ Cos A

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you both! the pictures i think is easier to remember though.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.