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lgbasallote

Lgbariddle!! is \[\huge a^{\frac mn} = \sqrt[n]{a^m} = (\sqrt[n] a)^m\]

  • one year ago
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  1. decripter37
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    yup

    • one year ago
  2. punnus
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    Can be proved

    • one year ago
  3. lgbasallote
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    so tell me...what happens when a is negative?

    • one year ago
  4. lgbasallote
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    for example \[\huge (-1)^{2/4}\]

    • one year ago
  5. lgbasallote
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    \[\huge \sqrt[4]{-1} \implies \text{imaginary}\] \[\huge \sqrt[4] {(-1)^2} \implies 1\]

    • one year ago
  6. decripter37
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    you're right, again

    • one year ago
  7. lgbasallote
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    that's where your algebra is now shaken :troll:

    • one year ago
  8. lgbasallote
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    this is the part where i advertise this: http://openstudy.com/updates/4fdaecf3e4b0f2662fd13fd6

    • one year ago
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