lgbasallote
  • lgbasallote
Lgbariddle!! is \[\huge a^{\frac mn} = \sqrt[n]{a^m} = (\sqrt[n] a)^m\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
yup
anonymous
  • anonymous
Can be proved
lgbasallote
  • lgbasallote
so tell me...what happens when a is negative?

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lgbasallote
  • lgbasallote
for example \[\huge (-1)^{2/4}\]
lgbasallote
  • lgbasallote
\[\huge \sqrt[4]{-1} \implies \text{imaginary}\] \[\huge \sqrt[4] {(-1)^2} \implies 1\]
anonymous
  • anonymous
you're right, again
lgbasallote
  • lgbasallote
that's where your algebra is now shaken :troll:
lgbasallote
  • lgbasallote
this is the part where i advertise this: http://openstudy.com/updates/4fdaecf3e4b0f2662fd13fd6

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