anonymous
  • anonymous
Prove that x=40
Mathematics
jamiebookeater
  • jamiebookeater
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TheViper
  • TheViper
Any question ??
anonymous
  • anonymous
x=40, done
anonymous
  • anonymous
drawing my diagram~ wait~ sorry~

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TheViper
  • TheViper
:)
anonymous
  • anonymous
XD don't worry
TheViper
  • TheViper
good drawing xD
anonymous
  • anonymous
1 Attachment
zzr0ck3r
  • zzr0ck3r
you drew that?
anonymous
  • anonymous
yeap ~
anonymous
  • anonymous
|dw:1346932456806:dw|
anonymous
  • anonymous
Now, use Sum of all angles of a triangle = 180
anonymous
  • anonymous
The two adjacent line are a tangent tot eh circle and also thery along with the lines forming the 70 angle form a quadrilateral. The sum of angles in a quadrilateral is 360 and angle formed by tangent is 90. Now I guess you can solve
anonymous
  • anonymous
@sauravshakya thanks :))
anonymous
  • anonymous
Welcomx
anonymous
  • anonymous
@punnus the angle u are saying is not 90 because the lines are not radius or diameter
anonymous
  • anonymous
I know that. I wants trying to give hints to solve the question and not the solution.
anonymous
  • anonymous
Were @sauravshakya were you able to tell her why the rest of the angles of the triangle are 70.
anonymous
  • anonymous
Angle between a tangent and a chord at the point of contact is equal to the opposite angle formed by the chord at the circumference
anonymous
  • anonymous
@punnus it's one of the rules in a circle i know~but thanks anyway~ :)
anonymous
  • anonymous
Ya.. its a theorem
anonymous
  • anonymous
@sauravshakya Do you know how that your theorem has come about...
anonymous
  • anonymous
It is a derived theorem...
anonymous
  • anonymous
derived using other theorems.
anonymous
  • anonymous
Actually its not my theorem.. BUT IF u are asking for a proof then U can search it on google
anonymous
  • anonymous
I know the proof of this so called theorem...
anonymous
  • anonymous
My point is that when ever you solve a question solve it frm the basic theorems that are present and not the derived ones
anonymous
  • anonymous
@sauravshakya If you want i can prove it for you right now...
anonymous
  • anonymous
I also know the proof..... But if u r willing to prove it then OK PLZ TAKE YOUR PRECIOUS TIME AND PROVE IT
anonymous
  • anonymous
To know how to use the theorem is better then to know the proof of it

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