Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
2^n>1001 log2^n>1001 nlog2>1001 n>1001/log2
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Does it help?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i think that's 2^(n1)....
 2 years ago

robinfr93 Group TitleBest ResponseYou've already chosen the best response.0
\[2^{n1} > 1000\] Find the least value of n
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
yes...i think lg is correct
 2 years ago

robinfr93 Group TitleBest ResponseYou've already chosen the best response.0
answer according to the text is 11.
 2 years ago

robinfr93 Group TitleBest ResponseYou've already chosen the best response.0
i.e, n = 11
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
2^(n1)>1000 log2^(n1)>log1000 (n1)log2>log1000 n1>log1000/log2 n1>9.965 n>10.965
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Welcomx
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[2^{10}=1024\] \[2^{111}=1024\]
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.