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robinfr93

if 2^n-1 > 1000 Find the least value of n.

  • one year ago
  • one year ago

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  1. sauravshakya
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    2^n>1001 log2^n>1001 nlog2>1001 n>1001/log2

    • one year ago
  2. sauravshakya
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    Does it help?

    • one year ago
  3. lgbasallote
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    i think that's 2^(n-1)....

    • one year ago
  4. robinfr93
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    \[2^{n-1} > 1000\] Find the least value of n

    • one year ago
  5. Yahoo!
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    yes...i think lg is correct

    • one year ago
  6. sauravshakya
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    Oh..

    • one year ago
  7. robinfr93
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    answer according to the text is 11.

    • one year ago
  8. robinfr93
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    i.e, n = 11

    • one year ago
  9. sauravshakya
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    2^(n-1)>1000 log2^(n-1)>log1000 (n-1)log2>log1000 n-1>log1000/log2 n-1>9.965 n>10.965

    • one year ago
  10. robinfr93
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    thanx :D

    • one year ago
  11. sauravshakya
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    Welcomx

    • one year ago
  12. UnkleRhaukus
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    \[2^{10}=1024\] \[2^{11-1}=1024\]

    • one year ago
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