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sauravshakyaBest ResponseYou've already chosen the best response.2
2^n>1001 log2^n>1001 nlog2>1001 n>1001/log2
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i think that's 2^(n1)....
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
\[2^{n1} > 1000\] Find the least value of n
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
yes...i think lg is correct
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
answer according to the text is 11.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
2^(n1)>1000 log2^(n1)>log1000 (n1)log2>log1000 n1>log1000/log2 n1>9.965 n>10.965
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[2^{10}=1024\] \[2^{111}=1024\]
 one year ago
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