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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2hint: use of distributive property (x+y)*(w+z)= x*w + x*z + y*w + y*z does this help ?

tux
 3 years ago
Best ResponseYou've already chosen the best response.0This is what I got after using distribution: (A∩A^c)U(A∩B^c)U(B∩A^c)U(B∩B^c) As you can see I got (A∩A^c) In solution it is (AUA^c)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2@tux u are absolutely correct there is printing mistake in that step, then again next step there is correct

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2because A∩A^c is null as shown there.

tux
 3 years ago
Best ResponseYou've already chosen the best response.0A U A^c = U A∩A^c={} You are right. Thanks

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2^^ thats right too. welcome :)
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