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Separate digits of a 3 digit number using mod, div.
I need help with separating the 2nd digit.
abc div 100=a
abc ? ?= b
abc mod 10=c
 one year ago
 one year ago
Separate digits of a 3 digit number using mod, div. I need help with separating the 2nd digit. abc div 100=a abc ? ?= b abc mod 10=c
 one year ago
 one year ago

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infinity_Best ResponseYou've already chosen the best response.0
let x E Z.How can we write it's last digit?
 one year ago

MelloBest ResponseYou've already chosen the best response.0
@infinity_ Sorry, what? I'm really new to this. Could you rephrase?
 one year ago

DavidificationBest ResponseYou've already chosen the best response.0
a=3digit number b=to store the output b=a%10 get the remaining out put(2 digits) and apply the same formula...
 one year ago

infinity_Best ResponseYou've already chosen the best response.0
@Mello the last digit of a number x is x%10, if you keep dividing x by 10 and getting remainder then you have what you want
 one year ago

sriramkumarBest ResponseYou've already chosen the best response.0
its as follows... start with a variable assigned to the mod of the number you have given then place the variable in a static array.... then assign the number to its divide... for ex: n=121 r=n%10; a[i]=r; n=n/10; put this thing ina while loop keeping the conditioon n>0 understood i hope... i've used C programming... u can modify it intto your coding language...
 one year ago
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