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tux

  • 3 years ago

Prove using set identities: (A∩B)U(A∩B^c)=A

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  1. helder_edwin
    • 3 years ago
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    \[ \large (A\cap B)\cup(A\cap B^c)=A\cap(B\cup B^c)=A\cap U=A \] where \(U\) is "the/a universe".

  2. tux
    • 3 years ago
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    Is this your first step? \[(A \cup A) \cap (A \cup B ^{c}) \cap (B \cup A) \cap (B \cup B^c)\]

  3. helder_edwin
    • 3 years ago
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    no. i factored A.

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