Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

in a graph where a liner equation intercept another liner equation. why is the intersection make the two equation equal.

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

because the two angles reflect eachother
a linear equation can be expressed in the form:\[y=mx+c\]which you have correctly drawn as a straight line graph

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

explain more please . thanks
now think of two linear equations - these would represent, say:\[y=m_1x+c_1\]and:\[y=m_2x+c_2\]
now, if these two lines intersect, then, at the point of intersection, the y-values of both must be equal - agreed?
agreed .
therefore, we can say:\[m_1x+c_1=m_2x+c_2\]at the point of intersection
which is the same as saying:\[y=y\]
because y=y thats grate . amazing . tell if we have quadratic equations |dw:1346967366273:dw|
same applies for quads - except this time you will get two solutions for x instead of one that you got for the linear case
lets say
and each of these, in theory could give you two different y values
y1=x^2 +mx + c and y2=x^2 +mx + c
quads are usually written as:\[y=a_1x^2+b_1x+c_1\]and:\[y=a_2x^2+b_2x+c_2\]
so at the points of intersection we will have:\[a_1x^2+b_1x+c_1=a_2x^2+b_2x+c_2\]
which leads to a quadratic equation in x - solve to get the two values for x where these curves intersect
in general, we could have two curves defined by:\[y=f(x)\]and:\[y=g(x)\] |dw:1346967756823:dw|
and, at each point of intersection, the y and x values on each curve are equal
I hope I have explained it well enough for you - let me know if you require any more explanation
have outdone yourself
many thanks.
thx - and you are welcome my friend! :)
what is the highest think your done in maths??
think == thing?
ya sorry
:) I have studied for a PhD in Aeronautical Engineering. but that was many years ago. I now teach maths as a hobby because I still enjoy it.
WOW, thats great. can send you some of my question from time to time?
I'm not sure what you mean by "send", but if you mean message me now and then if no one else is helping you - then yes, by all means do - I'll be glad to help out when I can.
by that i meant , the message on the top left corner. thanks
ok - thats fine.
am going to do a lot of calculus. nice one
but bear in mind that I may not always respond immediately because I also moderate this site so please don't think I'm ignoring you in those cases. :)
thanks. I will be patient . :)
gr8! speak to you later then...

Not the answer you are looking for?

Search for more explanations.

Ask your own question