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hal_stirrup
 2 years ago
in a graph where a liner equation intercept another liner equation. why is the intersection make the two equation equal.
hal_stirrup
 2 years ago
in a graph where a liner equation intercept another liner equation. why is the intersection make the two equation equal.

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hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1346965908373:dw

ifrah34
 2 years ago
Best ResponseYou've already chosen the best response.0because the two angles reflect eachother

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1a linear equation can be expressed in the form:\[y=mx+c\]which you have correctly drawn as a straight line graph

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0explain more please . thanks

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1now think of two linear equations  these would represent, say:\[y=m_1x+c_1\]and:\[y=m_2x+c_2\]

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1now, if these two lines intersect, then, at the point of intersection, the yvalues of both must be equal  agreed?

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1therefore, we can say:\[m_1x+c_1=m_2x+c_2\]at the point of intersection

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1which is the same as saying:\[y=y\]

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0because y=y thats grate . amazing . tell if we have quadratic equations dw:1346967366273:dw

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1same applies for quads  except this time you will get two solutions for x instead of one that you got for the linear case

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1346967476493:dw

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1and each of these, in theory could give you two different y values

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0y1=x^2 +mx + c and y2=x^2 +mx + c

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1quads are usually written as:\[y=a_1x^2+b_1x+c_1\]and:\[y=a_2x^2+b_2x+c_2\]

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1so at the points of intersection we will have:\[a_1x^2+b_1x+c_1=a_2x^2+b_2x+c_2\]

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1which leads to a quadratic equation in x  solve to get the two values for x where these curves intersect

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1in general, we could have two curves defined by:\[y=f(x)\]and:\[y=g(x)\] dw:1346967756823:dw

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1and, at each point of intersection, the y and x values on each curve are equal

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1I hope I have explained it well enough for you  let me know if you require any more explanation

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0have outdone yourself

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1thx  and you are welcome my friend! :)

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0what is the highest think your done in maths??

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1:) I have studied for a PhD in Aeronautical Engineering. but that was many years ago. I now teach maths as a hobby because I still enjoy it.

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0WOW, thats great. can send you some of my question from time to time?

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1I'm not sure what you mean by "send", but if you mean message me now and then if no one else is helping you  then yes, by all means do  I'll be glad to help out when I can.

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0by that i meant , the message on the top left corner. thanks

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0am going to do a lot of calculus. nice one

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1but bear in mind that I may not always respond immediately because I also moderate this site so please don't think I'm ignoring you in those cases. :)

hal_stirrup
 2 years ago
Best ResponseYou've already chosen the best response.0thanks. I will be patient . :)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1gr8! speak to you later then...
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