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in a graph where a liner equation intercept another liner equation. why is the intersection make the two equation equal.
 one year ago
 one year ago
in a graph where a liner equation intercept another liner equation. why is the intersection make the two equation equal.
 one year ago
 one year ago

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hal_stirrupBest ResponseYou've already chosen the best response.0
dw:1346965908373:dw
 one year ago

ifrah34Best ResponseYou've already chosen the best response.0
because the two angles reflect eachother
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
a linear equation can be expressed in the form:\[y=mx+c\]which you have correctly drawn as a straight line graph
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
explain more please . thanks
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
now think of two linear equations  these would represent, say:\[y=m_1x+c_1\]and:\[y=m_2x+c_2\]
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
now, if these two lines intersect, then, at the point of intersection, the yvalues of both must be equal  agreed?
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
therefore, we can say:\[m_1x+c_1=m_2x+c_2\]at the point of intersection
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
which is the same as saying:\[y=y\]
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
because y=y thats grate . amazing . tell if we have quadratic equations dw:1346967366273:dw
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
same applies for quads  except this time you will get two solutions for x instead of one that you got for the linear case
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
dw:1346967476493:dw
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
and each of these, in theory could give you two different y values
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
y1=x^2 +mx + c and y2=x^2 +mx + c
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
quads are usually written as:\[y=a_1x^2+b_1x+c_1\]and:\[y=a_2x^2+b_2x+c_2\]
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
so at the points of intersection we will have:\[a_1x^2+b_1x+c_1=a_2x^2+b_2x+c_2\]
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
which leads to a quadratic equation in x  solve to get the two values for x where these curves intersect
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
in general, we could have two curves defined by:\[y=f(x)\]and:\[y=g(x)\] dw:1346967756823:dw
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
dw:1346967787868:dw
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
and, at each point of intersection, the y and x values on each curve are equal
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
I hope I have explained it well enough for you  let me know if you require any more explanation
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
have outdone yourself
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
thx  and you are welcome my friend! :)
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
what is the highest think your done in maths??
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
:) I have studied for a PhD in Aeronautical Engineering. but that was many years ago. I now teach maths as a hobby because I still enjoy it.
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
WOW, thats great. can send you some of my question from time to time?
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
I'm not sure what you mean by "send", but if you mean message me now and then if no one else is helping you  then yes, by all means do  I'll be glad to help out when I can.
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
by that i meant , the message on the top left corner. thanks
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
am going to do a lot of calculus. nice one
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
but bear in mind that I may not always respond immediately because I also moderate this site so please don't think I'm ignoring you in those cases. :)
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
thanks. I will be patient . :)
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
gr8! speak to you later then...
 one year ago
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