Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

burhan101

  • 3 years ago

Factor: s⁶-27t⁹ using difference of cubes please

  • This Question is Closed
  1. lgbasallote
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hint \[\huge s^6 - 27t^9 \implies (s^2)^3 - (3t^3)^3\] does that help?

  2. lgbasallote
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    formula for difference of cubes is \[\huge a^3 - b^3 = (a-b)(a^2 + ab + b^2)\]

  3. burhan101
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1346971456209:dw|

  4. lgbasallote
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    your second factor is right..

  5. lgbasallote
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    but the first factor is just (a-b) not (a^3 - b^3)^3

  6. burhan101
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1346971679499:dw| would this be correct ?

  7. burhan101
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1346971944491:dw| @lgbasallote

  8. lgbasallote
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yup better

  9. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy