burhan101
Factor: s⁶27t⁹
using difference of cubes please



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lgbasallote
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hint \[\huge s^6  27t^9 \implies (s^2)^3  (3t^3)^3\]
does that help?

lgbasallote
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formula for difference of cubes is \[\huge a^3  b^3 = (ab)(a^2 + ab + b^2)\]

burhan101
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dw:1346971456209:dw

lgbasallote
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your second factor is right..

lgbasallote
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but the first factor is just (ab) not (a^3  b^3)^3

burhan101
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dw:1346971679499:dw would this be correct ?

burhan101
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dw:1346971944491:dw @lgbasallote

lgbasallote
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yup better