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burhan101 Group Title

Factor: s⁶-27t⁹ using difference of cubes please

  • 2 years ago
  • 2 years ago

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  1. lgbasallote Group Title
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    hint \[\huge s^6 - 27t^9 \implies (s^2)^3 - (3t^3)^3\] does that help?

    • 2 years ago
  2. lgbasallote Group Title
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    formula for difference of cubes is \[\huge a^3 - b^3 = (a-b)(a^2 + ab + b^2)\]

    • 2 years ago
  3. burhan101 Group Title
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    |dw:1346971456209:dw|

    • 2 years ago
  4. lgbasallote Group Title
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    your second factor is right..

    • 2 years ago
  5. lgbasallote Group Title
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    but the first factor is just (a-b) not (a^3 - b^3)^3

    • 2 years ago
  6. burhan101 Group Title
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    |dw:1346971679499:dw| would this be correct ?

    • 2 years ago
  7. burhan101 Group Title
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    |dw:1346971944491:dw| @lgbasallote

    • 2 years ago
  8. lgbasallote Group Title
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    yup better

    • 2 years ago
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