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lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
is that \[\huge \frac 1{2m} (4m^2  2mn)= 2m^3 + m^2n\]
 one year ago

Mathhelp346 Group TitleBest ResponseYou've already chosen the best response.1
yes except the m isnt in the denominator
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
ooh...well then \[\huge \frac 12 m ( 4m^2  2mn)\] distribute \[\huge \implies \frac{4m^2 \times m}2  \frac{2mn \times m}2\] multiply.. \[\huge \implies 2m^3 + m^2 n\] so yeah you're right
 one year ago

Mathhelp346 Group TitleBest ResponseYou've already chosen the best response.1
ok thanks
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
welcome
 one year ago

Mathhelp346 Group TitleBest ResponseYou've already chosen the best response.1
lol thanks
 one year ago
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