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Mathhelp346

  • 3 years ago

Does -1/2m(4m^2-2mn)=-2m^3+m^2n?

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  1. lgbasallote
    • 3 years ago
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    is that \[\huge -\frac 1{2m} (4m^2 - 2mn)= -2m^3 + m^2n\]

  2. Mathhelp346
    • 3 years ago
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    yes except the m isnt in the denominator

  3. lgbasallote
    • 3 years ago
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    ooh...well then \[\huge -\frac 12 m ( 4m^2 - 2mn)\] distribute \[\huge \implies -\frac{4m^2 \times m}2 - \frac{-2mn \times m}2\] multiply.. \[\huge \implies -2m^3 + m^2 n\] so yeah you're right

  4. Mathhelp346
    • 3 years ago
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    ok thanks

  5. lgbasallote
    • 3 years ago
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    welcome

  6. Mathhelp346
    • 3 years ago
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    lol thanks

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