85295james
Simplify the rational expression. State any excluded values.
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85295james
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x-2/x^2+3x-10
mathslover
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is this the question? :
\[\large{\frac{x-2}{x^2+3x-10}}\] ?
85295james
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yes that is it
KingGeorge
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Can you factor the denominator?
85295james
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what do you mean ??
85295james
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x=-5 or x=2
KingGeorge
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Right. So that means \(x^2+3x-10=(x+5)(x-2)\). That means your rational expression becomes\[\frac{(x-2)}{(x+5)(x-2)}\]Before we go farther, can you tell me what the excluded values will be?
85295james
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i dont know :(
KingGeorge
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The excluded values are the zeroes of the denominator. So you get \(x=-5,2\). Now I'm sure that you can simplify it.
85295james
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so x=0
KingGeorge
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You have excluded values when your denominator is 0.
Also, I've got to go now. If you have questions, I'll be back on later tonight, so I can answer your questions then.
85295james
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so x2
KingGeorge
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Do you mean \(x^2\)?
85295james
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no
KingGeorge
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x=2?
KingGeorge
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I'm a bit confused. Are you stuck with the simplification or the excluded values?
85295james
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sorry one secc
85295james
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|dw:1346987271707:dw|
85295james
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i dont think it is (A) now
85295james
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(C)????
KingGeorge
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It is not C. Look back at the equation. \[\frac{(x-2)}{(x+5)(x-2)}\]How can you simplify this?
85295james
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no
KingGeorge
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\[\frac{\cancel{(x-2)}}{(x+5)\cancel{(x-2)}}\]What do you get?
85295james
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(B)
KingGeorge
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no...You should get \[\frac{1}{(x+5)}\]
85295james
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o lol (D)