## Geometry_Hater 3 years ago Use quadratic formula to solve this equation 4x squared = 3x + 5

$$4x^2=3x+5$$ so$$4x^2-3x-5=0$$ Compare this ^^ quadratic equation with $$ax^2+bx+c=0$$ find a,b,c then the two rots of x are: $$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$