anonymous
  • anonymous
What is the area of a right triangle with Side a: 5√2 Side b: 4√2?
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
I got 10.. Formula to find right angle: A=1/2BH
anonymous
  • anonymous
find the side and then use use heros formula.

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anonymous
  • anonymous
side c.
anonymous
  • anonymous
You mean to find C?
anonymous
  • anonymous
yup
anonymous
  • anonymous
So i use: 5√2^2+4√^2=C^2
anonymous
  • anonymous
by using pythagourus theorm
anonymous
  • anonymous
18=C^2
anonymous
  • anonymous
So i do √18
anonymous
  • anonymous
thats 3redical2=c
anonymous
  • anonymous
2sides are in radical then 3rd should be also in radical. do you know radical mean?
anonymous
  • anonymous
Yes the X√x right?
anonymous
  • anonymous
yes great.
anonymous
  • anonymous
So it would be 9√2^2?
anonymous
  • anonymous
\[18=\sqrt{3*3*2}\] \[18=\sqrt{9*2}\] u know the square roof of 9 is 3 then \[18=3\sqrt{2}\]
anonymous
  • anonymous
Ok. So C=3√2
anonymous
  • anonymous
What is the Hero's formula?
anonymous
  • anonymous
therefor c=3redical2
anonymous
  • anonymous
A=5√2, B=4√2, C=3√2
anonymous
  • anonymous
do you know about Hero's formula ?
anonymous
  • anonymous
If it's a right triangle, you don't need Heron's formula . . .
anonymous
  • anonymous
I don't know Heron's formula. And yes, it is a Right Triangle
anonymous
  • anonymous
Multiply a×b then divide by 2.
anonymous
  • anonymous
Nice of you to join us, Cliff
anonymous
  • anonymous
*salutes* Heron's formula is general for any kind of triangle where you don't feel like using trigonometry to find the height. It requires that you know all three sides first, so often, you'll need trigonometry anyway.
anonymous
  • anonymous
5√2 * 4√2= 40 40/2= 20
anonymous
  • anonymous
QED. Good job.
anonymous
  • anonymous
yes i am in that i am talking about Hero's formula not herons.
anonymous
  • anonymous
Okay, good to know, i googled Heron's formula. Hero formula=Heron's formula
anonymous
  • anonymous
Same guy. Heron is another name for Hero of Alexandria (en.wikipedia.org/wiki/Hero_of_Alexandria)
anonymous
  • anonymous
ok me too.
anonymous
  • anonymous
I also, noted down Heron's formula for later use :D So the area: 20?
anonymous
  • anonymous
Thanks Muhammad !
anonymous
  • anonymous
Thanks cliff!
anonymous
  • anonymous
I have another question if one of you don't mind
anonymous
  • anonymous
its ok bro. u r welcome.
anonymous
  • anonymous
bro look at here what is says http://www.mathsisfun.com/geometry/herons-formula.html
anonymous
  • anonymous
Heron's formula is pretty cool, but I prefer using the Law of Sines and Law of Cosines better (provided you know at least 1 angle.
anonymous
  • anonymous
Step 2: Then calculate the Area using:
anonymous
  • anonymous
means we were dong right or wrong?
anonymous
  • anonymous
doing
anonymous
  • anonymous
i was doing without angles.
anonymous
  • anonymous
Area of any triangle is half the product of the base and height. For a right triangle, the two perpendicular legs are the base and height.
anonymous
  • anonymous
its easy for @Dallasb22
anonymous
  • anonymous
ok lets see by using herons formula.
anonymous
  • anonymous
Actually, you were doing it with angles because you saw the right angle and used Pythagoras' theorem for the third side (which was unnecessary).
anonymous
  • anonymous
Be my guest. Heron's formula is a beast and not worth my time.
anonymous
  • anonymous
Yes, receiving the third side is only necessary if we use Heron's formula.
anonymous
  • anonymous
Correct?
anonymous
  • anonymous
and if it wasn't a right angle, then you'd have to use law of cosines or law of sines to find the third side, and if you're going to use trig anyway, might as well solve for the height instead (which is easier) and you still don't need Heron's formula.
anonymous
  • anonymous
@CliffSedge Another right triangle, A=2√3 c=4 What do i do here?
anonymous
  • anonymous
Ah true, Cause 1/2BH=Area
anonymous
  • anonymous
I'd still only need base and height.
anonymous
  • anonymous
If you now have a leg and the hypotenuse, use PT to find the other leg then same as before.
anonymous
  • anonymous
As a fun exercise just to practice some arithmetic, you can use Heron's formula to verify the area, or vice-verse.
anonymous
  • anonymous
what are the answers of 1st question?
anonymous
  • anonymous
Okay, so 2√3^2+b^2=4^2 6+B^2=16
anonymous
  • anonymous
@muhammad9t5 Answer for Q1 is 20
anonymous
  • anonymous
So i subtract 6 to both sides B^2=10
anonymous
  • anonymous
B=√10
anonymous
  • anonymous
mm, something doesn't look right there..
anonymous
  • anonymous
They want my answer to be x√x
anonymous
  • anonymous
I think you forgot to square the 2 in (2√3)
anonymous
  • anonymous
Ahhhh. Thats my PROBLEM!!!
anonymous
  • anonymous
So it'd be 4√9 = 12
anonymous
  • anonymous
Side B= 2
anonymous
  • anonymous
So I would multiply A and B 2√3 * 2 =X x/2=Area?
anonymous
  • anonymous
Giving me an area of: 4√3
anonymous
  • anonymous
did you divide by 2?
anonymous
  • anonymous
Ah man. *facepalm*
anonymous
  • anonymous
2√3 IS the area
anonymous
  • anonymous
Math teaches us to be precise and methodical, yes?
anonymous
  • anonymous
Hehe, yes it does.
anonymous
  • anonymous
I have 2 more if you don't mind.
anonymous
  • anonymous
They should be easy, they are equilateral.
anonymous
  • anonymous
I just am doing something wrong that I can't find..
anonymous
  • anonymous
And remember, that is more important than any particular kind of math problem. It's the problem-solving attitude, the patience, the planning, that is more important than whether or not you can solve this or that equation.
anonymous
  • anonymous
yes.
anonymous
  • anonymous
Wanna take this equilateral triangle, muhammad? I'm going to take a coffee break.
anonymous
  • anonymous
Yes, i know what you mean. If you didn't catch me I would have gotten it wrong, because I was rushing.
anonymous
  • anonymous
All three sides: 5, so the perimeter: 15 What is the area?
anonymous
  • anonymous
Equilateral triangle area formula: √3/4 * (s^2)
anonymous
  • anonymous
So √3/4 * (25)
anonymous
  • anonymous
I get: 25√3/4
anonymous
  • anonymous
|dw:1347039793370:dw|
anonymous
  • anonymous
But i cannot insert that in my work, i can only enter x√x
anonymous
  • anonymous
hmm, I'm getting something different. I'm going to doublecheck my work. In the meantime, if you forget the equilateral triangle formula, you can rederive it using (what else?) Pythagoras' theorem. |dw:1347039924563:dw|
anonymous
  • anonymous
But what use is PT, if all side's are equal?
anonymous
  • anonymous
To solve for the height of the triangle, which you need for the general triangle area formula.
anonymous
  • anonymous
Okay.. So the height is 25? 25+25=25 50=25 25
anonymous
  • anonymous
Wait.. I did that wrong.
anonymous
  • anonymous
|dw:1347040273270:dw|
anonymous
  • anonymous
IF the sides are all 5, then AB is 2.5
anonymous
  • anonymous
So how do i put 2.5 into PT?
anonymous
  • anonymous
|dw:1347040269678:dw| \[(S/2)^2+h^2=S^2 \rightarrow h^2=S^2-S^2/4 = 3S^2/4\]
anonymous
  • anonymous
Half of 5 is (5/2). (5/2)^2 = 25/4. (tip: fractions are better than decimals when doing algebra)
anonymous
  • anonymous
I doublechecked. Your original formula and answer were correct.
anonymous
  • anonymous
How could that be?
anonymous
  • anonymous
How could what be?
anonymous
  • anonymous
25√3/4 is the answer?
anonymous
  • anonymous
Yep. If wherever you are submitting these answers doesn't like it in fraction form, then convert 25/4 into a decimal.
anonymous
  • anonymous
Being 6.25?
anonymous
  • anonymous
Yes. 2.5^2 = 6.25 just like 25^2 = 625.
anonymous
  • anonymous
But wait.. Something is wrong, because they want my answer as: x√x
anonymous
  • anonymous
And 6.25√3 is no good?
anonymous
  • anonymous
Darn, there i go again I forgot we were only simplifying the 25/4
anonymous
  • anonymous
I kept including the 25√3
anonymous
  • anonymous
I included the radical in the the division...
anonymous
  • anonymous
So its 25/4√3 Or 6.25√3
anonymous
  • anonymous
Your Score: 100.0% Thanks Cliff.
anonymous
  • anonymous
Those 2 were the only ones I was having trouble with.
anonymous
  • anonymous
My pleasure. They're all just puzzles. Keep looking until you find where all the pieces fit.
anonymous
  • anonymous
:)

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