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I got 10..
Formula to find right angle:
A=1/2BH

find the side and then use use heros formula.

side c.

You mean to find C?

yup

So i use: 5√2^2+4√^2=C^2

by using pythagourus theorm

18=C^2

So i do √18

thats 3redical2=c

2sides are in radical then 3rd should be also in radical. do you know radical mean?

Yes the X√x right?

yes great.

So it would be 9√2^2?

\[18=\sqrt{3*3*2}\]
\[18=\sqrt{9*2}\]
u know the square roof of 9 is 3 then
\[18=3\sqrt{2}\]

Ok.
So C=3√2

What is the Hero's formula?

therefor c=3redical2

A=5√2, B=4√2, C=3√2

do you know about Hero's formula ?

If it's a right triangle, you don't need Heron's formula . . .

I don't know Heron's formula. And yes, it is a Right Triangle

Multiply a×b then divide by 2.

Nice of you to join us, Cliff

5√2 * 4√2= 40
40/2= 20

QED. Good job.

yes i am in that i am talking about Hero's formula not herons.

Okay, good to know, i googled Heron's formula. Hero formula=Heron's formula

Same guy. Heron is another name for Hero of Alexandria (en.wikipedia.org/wiki/Hero_of_Alexandria)

ok me too.

I also, noted down Heron's formula for later use :D
So the area: 20?

Thanks Muhammad !

Thanks cliff!

I have another question if one of you don't mind

its ok bro. u r welcome.

bro look at here what is says http://www.mathsisfun.com/geometry/herons-formula.html

Step 2: Then calculate the Area using:

means we were dong right or wrong?

doing

i was doing without angles.

its easy for @Dallasb22

ok lets see by using herons formula.

Be my guest. Heron's formula is a beast and not worth my time.

Yes, receiving the third side is only necessary if we use Heron's formula.

Correct?

@CliffSedge Another right triangle,
A=2√3 c=4
What do i do here?

Ah true, Cause 1/2BH=Area

I'd still only need base and height.

If you now have a leg and the hypotenuse, use PT to find the other leg then same as before.

what are the answers of 1st question?

Okay, so
2√3^2+b^2=4^2
6+B^2=16

@muhammad9t5 Answer for Q1 is 20

So i subtract 6 to both sides
B^2=10

B=√10

mm, something doesn't look right there..

They want my answer to be x√x

I think you forgot to square the 2 in (2√3)

Ahhhh. Thats my PROBLEM!!!

So it'd be 4√9 = 12

Side B= 2

So I would multiply A and B
2√3 * 2 =X
x/2=Area?

Giving me an area of: 4√3

did you divide by 2?

Ah man. *facepalm*

2√3 IS the area

Math teaches us to be precise and methodical, yes?

Hehe, yes it does.

I have 2 more if you don't mind.

They should be easy, they are equilateral.

I just am doing something wrong that I can't find..

yes.

Wanna take this equilateral triangle, muhammad? I'm going to take a coffee break.

All three sides: 5, so the perimeter: 15
What is the area?

Equilateral triangle area formula: √3/4 * (s^2)

So √3/4 * (25)

I get: 25√3/4

|dw:1347039793370:dw|

But i cannot insert that in my work, i can only enter x√x

But what use is PT, if all side's are equal?

To solve for the height of the triangle, which you need for the general triangle area formula.

Okay.. So the height is 25?
25+25=25
50=25
25

Wait.. I did that wrong.

|dw:1347040273270:dw|

IF the sides are all 5, then AB is 2.5

So how do i put 2.5 into PT?

|dw:1347040269678:dw|
\[(S/2)^2+h^2=S^2 \rightarrow h^2=S^2-S^2/4 = 3S^2/4\]

Half of 5 is (5/2). (5/2)^2 = 25/4.
(tip: fractions are better than decimals when doing algebra)

I doublechecked. Your original formula and answer were correct.

How could that be?

How could what be?

25√3/4 is the answer?

Being 6.25?

Yes. 2.5^2 = 6.25 just like 25^2 = 625.

But wait.. Something is wrong, because they want my answer as: x√x

And 6.25√3 is no good?

Darn, there i go again
I forgot we were only simplifying the 25/4

I kept including the 25√3

I included the radical in the the division...

So its 25/4√3
Or 6.25√3

Your Score: 100.0%
Thanks Cliff.

Those 2 were the only ones I was having trouble with.

My pleasure. They're all just puzzles. Keep looking until you find where all the pieces fit.

:)