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Composition of functions?

Mathematics
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Yes ma'am.
I think that this is pretty easy for you. We know,\[(g \circ f)(x) = g(f(x)) \]Therefore, our composition simplifies as the following:\[(g \circ f)(x) \implies g(f(x)) \implies g(2x - 1) \implies (2x - 1) +2 \]

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Other answers:

Do you get the above?
... or should I be more informal? lol
I don't understand what composition means :I
Never mind that "composition" word. lol
Do you still understand my explanation?
No. I don't understand what I'm supposed to be doing at all! :'(
I'd give you an example.\[\sqrt{x + 1} \]We're doing two things to \(x\). First, we are finding the square root of x, then we are adding 1 to x. So,\[x + 1\]is the composition of two functions: \(\sqrt{\text{stuff}}\) and \(\text{stuff} + 1\).
Here, we are again doing two things to \(x\). First, we are multiplying two to it and adding 1(which is \(2x - 1\)) Then, we are adding two to that number.
Operation Multiply Two And Subtract 1 got a boring name, which is f(x). Operation Add Two To Whatever Comes In Our Way got the name g(x).
\(x\) went to Operation Multiply Two And Subtract 1, and then became \(2x - 1\). Sad :(
And then it went to Operation Add Two To Whatever Comes In Our Way and became \(2x - 1 + 2 = 2x + 1\)

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