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mukushla
 3 years ago
before going to bed :)
Particle P satisfies the differential equation\[ \frac{\text{d}\mathbf{r}}{\text{d}t}=\mathbf{c}\times \mathbf{r}\]show that P moves with a constant speed on a circular path.
where c is a constant vector
mukushla
 3 years ago
before going to bed :) Particle P satisfies the differential equation\[ \frac{\text{d}\mathbf{r}}{\text{d}t}=\mathbf{c}\times \mathbf{r}\]show that P moves with a constant speed on a circular path. where c is a constant vector

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CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.1If c is constant then crossproduct unnecessary, right? It's a scalar multiple?

henpen
 3 years ago
Best ResponseYou've already chosen the best response.0I'm tempted to say experiment, as electrons do this (Lorentz force), even though it's second derivatives involved the result looks very similar. It's not the answer, but it's an interesting analogy.

henpen
 3 years ago
Best ResponseYou've already chosen the best response.0And obviously it wouldn't always be circular, unless it starts of perpendicular, that would be circular if you looked parallel to the cfeild. And if it starts parallel, then it's just a straight line, but I'm avoiding the question.
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