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How to write as a simple logarithm:
log a + log (a+b)  log c  log d
 one year ago
 one year ago
How to write as a simple logarithm: log a + log (a+b)  log c  log d
 one year ago
 one year ago

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AnimalAinBest ResponseYou've already chosen the best response.1
The rules of logarithms are important here:\[\log(AB)=logA+logB\]\[\log(\frac{A}{B})=logAlogB\]
 one year ago

Cutiepo0Best ResponseYou've already chosen the best response.0
I got as far as log (((a^2)+ab)/(c/d))
 one year ago

Cutiepo0Best ResponseYou've already chosen the best response.0
but in the answer, the bottom of the equation is cd not c/d and I don't get why :(
 one year ago

AnimalAinBest ResponseYou've already chosen the best response.1
Working from that,\[\log a + \log (a+b)  \log c  \log d=\log(\frac{a(a+b)}{cd})\]
 one year ago

AnimalAinBest ResponseYou've already chosen the best response.1
OK, this time stepbystep. From the product rule\[\log a + \log (a+b)  \log c  \log d=\log[a(a+b)]\log c\log d\]
 one year ago

AnimalAinBest ResponseYou've already chosen the best response.1
Now, from the quotient rule\[\log[a(a+b)]−logc−logd=\log[\frac{a(a+b)}{c}]logd\]
 one year ago

AnimalAinBest ResponseYou've already chosen the best response.1
Apply the quotient rule again, to get\[\log[\frac{a(a+b)}{c}]−logd=\log[\frac{a(a+b)}{cd}]\]
 one year ago

Cutiepo0Best ResponseYou've already chosen the best response.0
and then with log d you do the same step as the last time!! Oh! How did you know to do the c first and then d though, I just did the first two parts with the multiplication law, and thelast two with the division law, and then both together with the division law
 one year ago

AnimalAinBest ResponseYou've already chosen the best response.1
You eat an elephant one bite at a time. Do math the same way.
 one year ago

Cutiepo0Best ResponseYou've already chosen the best response.0
haha okay thanks so much :)
 one year ago
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