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why is
9sin(pi/3)= 9sqrt3/2
and
3tan(pi/4)=3
and
2 sec(pi/3)=4
and
5 cos(pi/4)= 5sqrt2
how would i figure these out?
 one year ago
 one year ago
why is 9sin(pi/3)= 9sqrt3/2 and 3tan(pi/4)=3 and 2 sec(pi/3)=4 and 5 cos(pi/4)= 5sqrt2 how would i figure these out?
 one year ago
 one year ago

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timo86mBest ResponseYou've already chosen the best response.0
try using the unit circle
 one year ago

farah2318Best ResponseYou've already chosen the best response.0
how would i memorize all of that
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
Continuously draw the unit circle?
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
That's how it works for martial arts, biology and combat situations :
 one year ago

farah2318Best ResponseYou've already chosen the best response.0
do they have unit circle for tan and sec?
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
here's what it says in my book
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
dw:1347081765068:dw That suffice?
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
i would advice you to atleast remember these 3 values : \(sin (\pi/6)=0.5\) or sin 30 =0.5 \(sin (\pi/3)=\sqrt{3}/2\) or sin 60 =\(\sqrt{3}/2\) \(sin (\pi/4)=1/\sqrt{2}\) or sin 45 =\(1/\sqrt{2}\) then you can easily derive any ratio with angles 30,45,60 degrees, using standard formulas like sin x= cos (90x) or cot x =cos x / sin x say cos 60 = sin (9060)= sin 30 = 0.5 tan 45 = sin 45 / cos 45 = sin 45 / sin (9045) = sin 45/sin 45 =1
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
from your question 2 sec \( \pi/3\)= 2/(cos\( \pi/3\) )= 2/(sin (\(\pi/2\pi/3))\)=2/sin \( \pi/6\)=2/0.5=2*2=4 5 cos (pi/4)=5 sin (pi/2pi/4)= 5 sin (pi/4) = 5/sqrt 2
 one year ago
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