- anonymous

A sailboat sail is triangular with a height 10ft greater than it's base. If the sails area is 72 sq ft, find it's base and height.

- chestercat

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- anonymous

did you try drawing a picture?

- anonymous

what's the area of a triangle in terms of height and base?

- anonymous

actually you dont really need a picture
A=1/2b*h

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## More answers

- anonymous

Ok so what's next?

- anonymous

so you have an equation for b and h

- anonymous

you need one more equation, since you have two unknowns.

- anonymous

Ok..

- anonymous

"a height 10ft greater than it's base."
try to write an equation based on that statement

- anonymous

I have no clue lol

- anonymous

i get lost on these problems

- anonymous

if b is 6 what is h?

- anonymous

10

- anonymous

because 10 is 10 more than 6?

- anonymous

yes

- anonymous

what's 6 plus 10

- anonymous

16

- anonymous

so 16 is 10 more than 6

- anonymous

if b=6 h=16

- anonymous

if b=7 h=?

- anonymous

16

- anonymous

?

- anonymous

because 16 is 10 more than 7...

- anonymous

so my answer is 7, 16

- anonymous

this was fun.

- anonymous

the computer again said that was wrong?

- anonymous

??

- anonymous

|dw:1347073516029:dw|

- anonymous

so what is my answer?

- anonymous

for the base and heig

- anonymous

t?

- anonymous

You have to solve for x.

- anonymous

X(x+10) / 2??

- anonymous

now?

- Agent47

Good job Denebel. KE, if you can't follow simple instructions, nobody will help you. Nobody is just going to post the answer.

- anonymous

\[72=\frac{ 1 }{ 2 }x(x+h)\]
Do you know how to solve for x?

- anonymous

Yes but it comes out to be like a square root.. I'm not stupid or anything

- anonymous

prove it.

- anonymous

prove what?

- anonymous

wow.

- anonymous

Um excuse me Mrs. wrong answer giver Algebraic I can block u also...

- anonymous

Ok, what did you do so far?

- anonymous

when I divided the equation u told me to divide i got 2 big square roots

- anonymous

?
Can you show me the steps? Draw or write it out.

- anonymous

I'm not even sure if i worked it right? I put it in my calcuator

- anonymous

If you don't mind me asking, what math are you taking?

- anonymous

Intermediate.

- anonymous

Is there a particular subject? On the cover of your textbook? Have you learned about distribution?

- anonymous

Also, how did you type x(x+10) in your calculator...

- anonymous

Have u ever used a graphing calucator?? u can type that in to that

- anonymous

what did you get for a base?

- anonymous

Yes the particular subject is intermediate math i believe i said that

- anonymous

I don't even know now people are making me mad on here tonight

- anonymous

well assuming you have a graphing calculator
i put down
(1/2)(x(x+10))-72
find when y=0
and got x=8

- anonymous

ok

- anonymous

sorry for above
shouldve check this sooner

- anonymous

huh?

- anonymous

|dw:1347075231860:dw|

- anonymous

duh ok i already knew that.... ...... but is that my base or height????

- anonymous

It's nothing, you have to solve for x first. It's just an equation so you find your base and height.

- anonymous

Ok did i just not solve this same one though?

- anonymous

Which other equation did you solve?

- anonymous

I thought i just solved this one

- anonymous

x=-18,8 ???? is that right

- anonymous

well the base cant be negative
so just x=8

- anonymous

Measurements of an object can be negative.
|dw:1347075538826:dw|

- anonymous

so my base is 8 and my height is -18???

- anonymous

so much fail.

- anonymous

what?

- anonymous

Oops typo there, I mean CAN'T

- anonymous

Denebel u have me lost...

- anonymous

the height was 10 more than the base
if the base if 8
8+10 =18
case closed

- anonymous

so my base is 18 and my height is 10?

- anonymous

@completeidiot Also has to satisfy A=72

- anonymous

no...
base is 8 height is 18......
8*18=144
144/2=72
GAHHHHHHHH

- anonymous

Oops sorry
My brain is wacked.
I typed it in my calculator wrong.

- anonymous

LOL Yes @KE8717504 , completeidiot is correct

- anonymous

THANK YOU SO MUCH @completeidiot

- anonymous

@Denebel i'm starting to wonder if u know what ur doing.. and u are very confusing.

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