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If a ball is thrown into the air with a v of 40 ft/s, it's height in ft t seconds late is given by y= 40t16t^2. Find the avg velocity for the time period beginning when t=2 & lasting 0.5 sec, 0.05 sec?
 one year ago
 one year ago
If a ball is thrown into the air with a v of 40 ft/s, it's height in ft t seconds late is given by y= 40t16t^2. Find the avg velocity for the time period beginning when t=2 & lasting 0.5 sec, 0.05 sec?
 one year ago
 one year ago

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Algebraic!Best ResponseYou've already chosen the best response.1
so the distance covered / the time interval is what you're looking for...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
do you know how to find the distance covered between t=2 and t=2.5?
 one year ago

math456Best ResponseYou've already chosen the best response.0
Yea it's like u plug in the 2 in the equation and then distance covered in 2distance coverd in 2.5/22.5
 one year ago

math456Best ResponseYou've already chosen the best response.0
So in this case is .5 sec= 0?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
find y(2) find y(2.5)
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
then find the difference between those two heights
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
then divide by the time interval (.5s)
 one year ago

math456Best ResponseYou've already chosen the best response.0
But 2.5 is not in the question..
 one year ago

math456Best ResponseYou've already chosen the best response.0
2.5 ohh gotch ya so all I do is divide by the 0.5, 0.05?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
don't think so... how'd you get that
 one year ago

math456Best ResponseYou've already chosen the best response.0
U r adding the values to 2.0?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
height at 2 seconds and height .05 seconds later ( y(2.05) )
 one year ago

math456Best ResponseYou've already chosen the best response.0
so for 0.01 second its y(2)y(2.01)
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
\[(d _{f}  d _{i})/(t _{f} t _{i})\]
 one year ago

math456Best ResponseYou've already chosen the best response.0
okay how abt if i want to find the estimate instantaneous velocity when t=2
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
if you're allowed to use calculus you just take the derivative...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
if not, you take the limit of the avg. velocity expression as t>0
 one year ago

math456Best ResponseYou've already chosen the best response.0
ummm not sure what u meant so when t=2 its t>0
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
the third alternative is using the equation that you might've been given where the derivative is already taken for you...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
something like \[V(t) = V _{o} +at\]
 one year ago

math456Best ResponseYou've already chosen the best response.0
can i just do like 3214.76M0.50.05N
 one year ago

math456Best ResponseYou've already chosen the best response.0
sorry here m is the divide sign
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
The three ways I mentioned are the ways to do it, not sure what you typed there or what you're trying to do.
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
You all good on this? Or do you have another question?
 one year ago

math456Best ResponseYou've already chosen the best response.0
how how can i take the limit of avg. velocity at t>0?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
for a specific value of t?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
I'll use the sketch pad to show you
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1347077529182:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
that's the first term...
 one year ago

math456Best ResponseYou've already chosen the best response.0
hmmm how do I find the delta t value?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1347077587650:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
that's the second term
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
all that gets divided by delta t
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
then you take the limit as delta t >0
 one year ago

math456Best ResponseYou've already chosen the best response.0
so the limit as x approaches to 0 is 16
 one year ago
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