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If a ball is thrown into the air with a v of 40 ft/s, it's height in ft t seconds late is given by y= 40t-16t^2. Find the avg velocity for the time period beginning when t=2 & lasting 0.5 sec, 0.05 sec?

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so the distance covered / the time interval is what you're looking for...
do you know how to find the distance covered between t=2 and t=2.5?
The average velocity!

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Other answers:

Yea it's like u plug in the 2 in the equation and then distance covered in 2-distance coverd in 2.5/2-2.5
So in this case is .5 sec= 0?
And 0.05=7.2
find y(2) find y(2.5)
then find the difference between those two heights
then divide by the time interval (.5s)
But 2.5 is not in the question..
2 + .5 = ?
2.5 ohh gotch ya so all I do is divide by the 0.5, 0.05?
So for 0.5 it's 32?
let me check
And for 0.05 is 320?
don't think so... how'd you get that
y(2) and y(2.05)
U r adding the values to 2.0?
height at 2 seconds and height .05 seconds later ( y(2.05) )
so for 0.01 second its y(2)-y(2.01)
\[(d _{f} - d _{i})/(t _{f} -t _{i})\]
okay how abt if i want to find the estimate instantaneous velocity when t=2
sorry t=1*
if you're allowed to use calculus you just take the derivative...
if not, you take the limit of the avg. velocity expression as t->0
ummm not sure what u meant so when t=2 its t>0
the third alternative is using the equation that you might've been given where the derivative is already taken for you...
something like \[V(t) = V _{o} +at\]
seen that before?
can i just do like 32-14.76M0.5-0.05N
yea i hv seen it
sorry here m is the divide sign
The three ways I mentioned are the ways to do it, not sure what you typed there or what you're trying to do.
You all good on this? Or do you have another question?
how how can i take the limit of avg. velocity at t>0?
for a specific value of t?
I'll use the sketch pad to show you
okay, thanks
that's the first term...
hmmm how do I find the delta t value?
that's the second term
all that gets divided by delta t
then you take the limit as delta t ->0
so the limit as x approaches to 0 is -16
for inst. velocity?
should be -24
let me check again..
okay got it nw..
thanks for ur help..
No problem!

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