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enticingly
Group Title
Which expression is equivalent to the sine of the angle γ for the triangle of area A shown below?
a. 2a/bc
b. a/c
c. b/c A
d. Not enough information
A. a
B. b
C. c
D. d
 one year ago
 one year ago
enticingly Group Title
Which expression is equivalent to the sine of the angle γ for the triangle of area A shown below? a. 2a/bc b. a/c c. b/c A d. Not enough information A. a B. b C. c D. d
 one year ago
 one year ago

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Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
that a right triangle?
 one year ago

enticingly Group TitleBest ResponseYou've already chosen the best response.0
dw:1347087195007:dw
 one year ago

enticingly Group TitleBest ResponseYou've already chosen the best response.0
OK THIS ONE IS MORE ACCURATE :)
 one year ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
Is that a right triangle?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
already asked that...
 one year ago

punnus Group TitleBest ResponseYou've already chosen the best response.1
see to solve this question draw a perpendicular on the side b. Now we know that the area of a right angled triangle is \[\frac{ 1 }{ 2 } \times base \times height\] Now we have two triangles with respective basedw:1347088112276:dw Now use the area formula. so the area of the truangle A is the combined area of the two triangles. \[A= \frac{ 1 }{ 2 } h \times (b1+b2)\] Now sin(y) is h/c. Replace h from sin(y) using area eqn and you will get the answer as \[\frac{ 2A }{ bc }\]
 one year ago

punnus Group TitleBest ResponseYou've already chosen the best response.1
@enticingly This solves your problem
 one year ago

enticingly Group TitleBest ResponseYou've already chosen the best response.0
@punnus thanks a bunch u got urself a medal for that ;)
 one year ago
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