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enticingly

  • 3 years ago

Which expression is equivalent to the sine of the angle γ for the triangle of area A shown below? a. 2a/bc b. a/c c. b/c A d. Not enough information A. a B. b C. c D. d

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  1. Algebraic!
    • 3 years ago
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    that a right triangle?

  2. enticingly
    • 3 years ago
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    |dw:1347087195007:dw|

  3. enticingly
    • 3 years ago
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    OK THIS ONE IS MORE ACCURATE :)

  4. Denebel
    • 3 years ago
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    Is that a right triangle?

  5. Algebraic!
    • 3 years ago
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    already asked that...

  6. enticingly
    • 3 years ago
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    No

  7. enticingly
    • 3 years ago
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    my bad

  8. punnus
    • 3 years ago
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    see to solve this question draw a perpendicular on the side b. Now we know that the area of a right angled triangle is \[\frac{ 1 }{ 2 } \times base \times height\] Now we have two triangles with respective base|dw:1347088112276:dw| Now use the area formula. so the area of the truangle A is the combined area of the two triangles. \[A= \frac{ 1 }{ 2 } h \times (b1+b2)\] Now sin(y) is h/c. Replace h from sin(y) using area eqn and you will get the answer as \[\frac{ 2A }{ bc }\]

  9. punnus
    • 3 years ago
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    @enticingly This solves your problem

  10. enticingly
    • 3 years ago
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    @punnus thanks a bunch u got urself a medal for that ;)

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