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hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think we need to use x+y>x+y but not sure.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
But wat Does that Least Value For?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i m just trying.... if z>=3 what can u say about 1/z ??
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
z ( 1/z) > = z  1/z
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
I Did nt Understand....wat is here Least..""
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
means z+1/z is > = 'some number' u need to find that number.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
but z+1/z <= z+1/z how did u get > sign there ?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
u see..i have inserted a ve there....Since it asks for least value."
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Hmm.. Am I right for this: z ≥ 3 i.e. z ≥ 3 or z ≤ 3 ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think z is complex here, isn't it @Yahoo! ??
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so z>= 3 represents region outside the circle with radius 3.....if i have not misinterpreted
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Wow! Something I don't know! I'm sorry!!
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
"OUTSIDE" hw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
because of > sign, if < then inside.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@hartnn Any Idea....
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i got something from yahoo answers , trying to understand it, see if that makes some sense to u..... http://in.answers.yahoo.com/question/index?qid=20100423221137AAAgV9K
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
i think we have to find the least dist b/w Circles
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@hartnn i Did nt Understand.....Can u Explain...
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
\[z \geq 3\implies z\leq3\;or\;z\geq3\] \(\leftz + \frac1z\right\) is just a symmetrical hyperbola about Yaxis. If you're well versed with hyperbola you will get the idea of the graph with constraint \(z\geq3\).
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
lol...i Dont knw Hyperbola....
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Okay. \[x + \frac1x\] \(x\) is ever increasing, so to find the minima of \(x + \frac1x\) you should find value for which \(x\) is minimum i.e 3 as \(1/x\) is decreasing for \(x>1\).
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Important to note \(1/x\) is decreasing not negative.
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Negative with respect to \(x\).
 one year ago

Pallavi06 Group TitleBest ResponseYou've already chosen the best response.0
express Z= x+ iy.......and its mod value is suar root of x^2 +y^2.....now mod of Z+1 can be expressed as (x+1 )+ iy......and then solve it.....i know its very lengthy but it works when u have no other option....
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
If r is the modulus of z, then z+ 1/z >= r  1/r. Now the minimum of r  1/r for r>=3 is clearly 3  1/3 = 8/3. The minimum for z+1/z is attained if z = 3 and if z and 1/z have opposite directions. Take z = 3i so that z = 1/3i =  i / 3, and the minimum 8/3 is attained for that value. Can u Explain this!
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
I was afk. Complex Numbers?
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
away from the keyboard.
 one year ago

Vaidehi09 Group TitleBest ResponseYou've already chosen the best response.0
yup. complex nos.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yes.. it is Complex Numbers
 one year ago

Pallavi06 Group TitleBest ResponseYou've already chosen the best response.0
let Z= x + iy and try to get value of mod 1/z
 one year ago

Pallavi06 Group TitleBest ResponseYou've already chosen the best response.0
can u do it?
 one year ago

Pallavi06 Group TitleBest ResponseYou've already chosen the best response.0
if mod z is r then ull get mod i/z as 1/r.....
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
I will be back, my trackpad isn't working somehow.
 one year ago

Vaidehi09 Group TitleBest ResponseYou've already chosen the best response.0
shouldn't it be this way? or is something wrong with this? dw:1347108277591:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
if its <= then its max value , not least value.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
The answer should be 8/3
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
and yes,thats the correct way to find max value.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
lol.....Can we Do like this z ( 1/z) > = z  1/z
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
= 3  1/3 = 8/3
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
is this true ? xy >= xy if yes, then u can do it like that.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
and i guess its true.
 one year ago
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