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hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think we need to use x+y>x+y but not sure.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
But wat Does that Least Value For?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i m just trying.... if z>=3 what can u say about 1/z ??
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
z ( 1/z) > = z  1/z
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
I Did nt Understand....wat is here Least..""
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
means z+1/z is > = 'some number' u need to find that number.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
but z+1/z <= z+1/z how did u get > sign there ?
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
u see..i have inserted a ve there....Since it asks for least value."
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Hmm.. Am I right for this: z ≥ 3 i.e. z ≥ 3 or z ≤ 3 ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think z is complex here, isn't it @Yahoo! ??
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so z>= 3 represents region outside the circle with radius 3.....if i have not misinterpreted
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Wow! Something I don't know! I'm sorry!!
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
"OUTSIDE" hw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
because of > sign, if < then inside.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@hartnn Any Idea....
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i got something from yahoo answers , trying to understand it, see if that makes some sense to u..... http://in.answers.yahoo.com/question/index?qid=20100423221137AAAgV9K
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
i think we have to find the least dist b/w Circles
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@hartnn i Did nt Understand.....Can u Explain...
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
\[z \geq 3\implies z\leq3\;or\;z\geq3\] \(\leftz + \frac1z\right\) is just a symmetrical hyperbola about Yaxis. If you're well versed with hyperbola you will get the idea of the graph with constraint \(z\geq3\).
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
lol...i Dont knw Hyperbola....
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Okay. \[x + \frac1x\] \(x\) is ever increasing, so to find the minima of \(x + \frac1x\) you should find value for which \(x\) is minimum i.e 3 as \(1/x\) is decreasing for \(x>1\).
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Important to note \(1/x\) is decreasing not negative.
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Negative with respect to \(x\).
 2 years ago

Pallavi06 Group TitleBest ResponseYou've already chosen the best response.0
express Z= x+ iy.......and its mod value is suar root of x^2 +y^2.....now mod of Z+1 can be expressed as (x+1 )+ iy......and then solve it.....i know its very lengthy but it works when u have no other option....
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
If r is the modulus of z, then z+ 1/z >= r  1/r. Now the minimum of r  1/r for r>=3 is clearly 3  1/3 = 8/3. The minimum for z+1/z is attained if z = 3 and if z and 1/z have opposite directions. Take z = 3i so that z = 1/3i =  i / 3, and the minimum 8/3 is attained for that value. Can u Explain this!
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
I was afk. Complex Numbers?
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
away from the keyboard.
 2 years ago

Vaidehi09 Group TitleBest ResponseYou've already chosen the best response.0
yup. complex nos.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yes.. it is Complex Numbers
 2 years ago

Pallavi06 Group TitleBest ResponseYou've already chosen the best response.0
let Z= x + iy and try to get value of mod 1/z
 2 years ago

Pallavi06 Group TitleBest ResponseYou've already chosen the best response.0
can u do it?
 2 years ago

Pallavi06 Group TitleBest ResponseYou've already chosen the best response.0
if mod z is r then ull get mod i/z as 1/r.....
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
I will be back, my trackpad isn't working somehow.
 2 years ago

Vaidehi09 Group TitleBest ResponseYou've already chosen the best response.0
shouldn't it be this way? or is something wrong with this? dw:1347108277591:dw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
if its <= then its max value , not least value.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
The answer should be 8/3
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
and yes,thats the correct way to find max value.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
lol.....Can we Do like this z ( 1/z) > = z  1/z
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
= 3  1/3 = 8/3
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
is this true ? xy >= xy if yes, then u can do it like that.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
and i guess its true.
 2 years ago
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