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zaphod

  • 2 years ago

A particle of mass 5kg is pulled along a smooth horizontal surfce by a horizontal string> if the acc of particle is 3ms-2find the tension

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  1. zaphod
    • 2 years ago
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    @Callisto can i kw hw to apply the forces?

  2. Callisto
    • 2 years ago
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    |dw:1347114640040:dw| Consider the horizontal, Summation F = T = ma = 5(3), isn't it?

  3. Callisto
    • 2 years ago
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    |dw:1347114778579:dw| The vertical forces cancel out..

  4. Callisto
    • 2 years ago
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    Note that smooth = friction = 0N Note sure if I'm in the right direction :|

  5. zaphod
    • 2 years ago
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    yes |dw:1347114907153:dw|

  6. Callisto
    • 2 years ago
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    Why did you add that T?

  7. zaphod
    • 2 years ago
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    in a horizontal string tension acts oppostely

  8. Callisto
    • 2 years ago
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    Hmm.. I'm actually considering this part..|dw:1347115073162:dw|

  9. zaphod
    • 2 years ago
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    yes then continue?

  10. Callisto
    • 2 years ago
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    For that system, weight is balanced by the normal reaction. So, vertical forces cancel. Consider the horizontal force, since the surface is 'smooth', there is no friction acting on the particle. The only horizontal force acting on the system is tension. So, by Newton's 2nd law, T - f = ma , where f = 0, m=5 and a=3 So, you can find T.

  11. Callisto
    • 2 years ago
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    f= 0N, m=5kg and a=3ms^-2

  12. zaphod
    • 2 years ago
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    :) get it why is force = 0

  13. keily
    • 2 years ago
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    Tension=5kg times 3m/s=15N

  14. Callisto
    • 2 years ago
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    f is friction acting on the system by the surface. But the surface is smooth, so no friction acting on the system

  15. Callisto
    • 2 years ago
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    Any questions?

  16. zaphod
    • 2 years ago
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    nope clear :)

  17. Callisto
    • 2 years ago
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    Great!

  18. zaphod
    • 2 years ago
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    i thought there is an external force making the particle move, anyway nw i understnd

  19. Callisto
    • 2 years ago
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    That external force is the tension. If you don't pull the string, there is no tension, the block doesn't move. Perhaps you can consider that system only. I mean the force applied to that system.

  20. zaphod
    • 2 years ago
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    yes thanks u so much :)

  21. Callisto
    • 2 years ago
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    Welcome :)

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