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ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
If it was not for the 101, it'd definitely have been 9.
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
hint: its not a 'conventional' series with a formula for nth term
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
I think I know this...
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
is it 5 ? my quess
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
guess *
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
in different bases :)
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
so it should be 1 I believe
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
yes and the next one is 5 also then 5,5,5.......
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
yey .... but I only guessed I will like to hear the right soln
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
101 = 5 in base 2 12 = 5 in base 3 11 = 5 in base 4 10 = 5 in base 5 5 = 5 in base 6
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
i think asnaseer has it
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
typo from me above 5 NOT 1
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
5,5,5,5,...
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
*nice question, i was thinking of different bases but still could not get this one.
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
jimmyrep gave me this one
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
\[\large \frac{\left(\frac{89(n1.5)}{n1.5}+\frac{(n2.5)}{n2.5}+\frac{n3.5}{n3.5}+5\frac{n4.5}{n4.5}+106\frac{n5.5}{n5.5}\right)}{2}\] i can get; ...,5,101,101,101 :)
 one year ago
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