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cwrw238

  • 3 years ago

how about this one 101, 12, 11, 10, ....

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  1. ParthKohli
    • 3 years ago
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    If it was not for the 101, it'd definitely have been 9.

  2. cwrw238
    • 3 years ago
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    yup

  3. cwrw238
    • 3 years ago
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    hint: its not a 'conventional' series with a formula for nth term

  4. asnaseer
    • 3 years ago
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    I think I know this...

  5. mathslover
    • 3 years ago
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    is it 5 ? my quess

  6. mathslover
    • 3 years ago
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    guess *

  7. asnaseer
    • 3 years ago
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    in different bases :)

  8. asnaseer
    • 3 years ago
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    so it should be 1 I believe

  9. cwrw238
    • 3 years ago
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    yes and the next one is 5 also then 5,5,5.......

  10. mathslover
    • 3 years ago
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    yey .... but I only guessed I will like to hear the right soln

  11. asnaseer
    • 3 years ago
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    101 = 5 in base 2 12 = 5 in base 3 11 = 5 in base 4 10 = 5 in base 5 5 = 5 in base 6

  12. cwrw238
    • 3 years ago
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    i think asnaseer has it

  13. asnaseer
    • 3 years ago
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    typo from me above 5 NOT 1

  14. cwrw238
    • 3 years ago
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    right!

  15. mukushla
    • 3 years ago
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    5,5,5,5,...

  16. hartnn
    • 3 years ago
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    *nice question, i was thinking of different bases but still could not get this one.

  17. cwrw238
    • 3 years ago
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    jimmyrep gave me this one

  18. amistre64
    • 3 years ago
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    \[\large -\frac{\left(\frac{89(n-1.5)}{|n-1.5|}+\frac{(n-2.5)}{|n-2.5|}+\frac{n-3.5}{|n-3.5|}+5\frac{n-4.5}{|n-4.5|}+106\frac{n-5.5}{|n-5.5|}\right)}{2}\] i can get; ...,5,-101,-101,-101 :)

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