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Iventer
can i say that the integral of tanx secxtanx = (-lncosx secx)
I don't think you can. Sorry for replying late I was afk.
i think thats tan x + tan x sec x isn't it?
it is integral of tanx secx tanx . i think i should sub with u to get du?
actually i have integral of secxsec^2x. then i try integration by parts. i have u= secx and dv= sec^2x. thats how i end up with tanx secx tanx.