chicagochica5
How many solutions does the system have?
x = 4y + 4
2x + 8y = 8
A. one solution
B. two solutions
C. infinitely many solutions
D. no solution



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ParthKohli
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Multiplying the first equation by 2:\[2x = 8y + 8 \]

ParthKohli
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Also, subtracting 8y from both sides in the second equation:\[2x = 8y + 8\]

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There is a lot of solutions

ParthKohli
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We now have the following equations:\[2x = 8y + 8\\2x = 8y + 8\]

ParthKohli
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A lot? Uncountable! Infinity!

ParthKohli
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lol

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yes a very lot

ParthKohli
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A lot lot lot lot!

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You can see that without solving the system.

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You can mentally arrange the unknows at the left hand side.
and see that the second equation is the first one multiplied by 2

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so you have only one equation with two unknows. that means a lot of solutions.