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chicagochica5

  • 2 years ago

How many solutions does the system have? x = -4y + 4 2x + 8y = 8 A. one solution B. two solutions C. infinitely many solutions D. no solution

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  1. ParthKohli
    • 2 years ago
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    Multiplying the first equation by 2:\[2x = -8y + 8 \]

  2. ParthKohli
    • 2 years ago
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    Also, subtracting 8y from both sides in the second equation:\[2x = -8y + 8\]

  3. No-data
    • 2 years ago
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    There is a lot of solutions

  4. ParthKohli
    • 2 years ago
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    We now have the following equations:\[2x = -8y + 8\\2x = -8y + 8\]

  5. ParthKohli
    • 2 years ago
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    A lot? Uncountable! Infinity!

  6. ParthKohli
    • 2 years ago
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    lol

  7. No-data
    • 2 years ago
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    yes a very lot

  8. ParthKohli
    • 2 years ago
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    A lot lot lot lot!

  9. No-data
    • 2 years ago
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    You can see that without solving the system.

  10. No-data
    • 2 years ago
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    You can mentally arrange the unknows at the left hand side. and see that the second equation is the first one multiplied by 2

  11. No-data
    • 2 years ago
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    so you have only one equation with two unknows. that means a lot of solutions.

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