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aroub

  • 3 years ago

(4sqrt of 81a^3)^5

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  1. asdfghjkl8063
    • 3 years ago
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    4.452

  2. Agent47
    • 3 years ago
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    4^5 * 3^5 *a^(15/2)

  3. ParthKohli
    • 3 years ago
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    \[\left(ab \right)^n = a^n b^n \]

  4. Agent47
    • 3 years ago
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    wait is a^3 inside the square root?

  5. aroub
    • 3 years ago
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    yeah

  6. Agent47
    • 3 years ago
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    oh ok, so then the answer i gave u shld be right

  7. ParthKohli
    • 3 years ago
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    \[\implies (4\sqrt{81a^3})^5 \]\[\implies 4^5 \times \left(\sqrt{81a^3} \right)^5\]

  8. ParthKohli
    • 3 years ago
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    simplify

  9. Agent47
    • 3 years ago
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    4^5 * 3^5 *a^(15/2) should be 4^5 * 9^5 *a^(15/2)

  10. aroub
    • 3 years ago
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    that becomes sqrt of 81 a^15?

  11. Agent47
    • 3 years ago
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    no, since you have: (4*sqrt(81*a^3))^5=4^5*(9*a^(3/2))^5=4^5*9^5*a^15*sqrt(a)

  12. aroub
    • 3 years ago
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    so confusing! >.<

  13. aroub
    • 3 years ago
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    Okay, the fraction exponent is confusing me. I think there is a way without using it, right?

  14. aroub
    • 3 years ago
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    Oh well :/ Thanks everyone! :)

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