aroub
  • aroub
(4sqrt of 81a^3)^5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
4.452
Agent47
  • Agent47
4^5 * 3^5 *a^(15/2)
ParthKohli
  • ParthKohli
\[\left(ab \right)^n = a^n b^n \]

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Agent47
  • Agent47
wait is a^3 inside the square root?
aroub
  • aroub
yeah
Agent47
  • Agent47
oh ok, so then the answer i gave u shld be right
ParthKohli
  • ParthKohli
\[\implies (4\sqrt{81a^3})^5 \]\[\implies 4^5 \times \left(\sqrt{81a^3} \right)^5\]
ParthKohli
  • ParthKohli
simplify
Agent47
  • Agent47
4^5 * 3^5 *a^(15/2) should be 4^5 * 9^5 *a^(15/2)
aroub
  • aroub
that becomes sqrt of 81 a^15?
Agent47
  • Agent47
no, since you have: (4*sqrt(81*a^3))^5=4^5*(9*a^(3/2))^5=4^5*9^5*a^15*sqrt(a)
aroub
  • aroub
so confusing! >.<
aroub
  • aroub
Okay, the fraction exponent is confusing me. I think there is a way without using it, right?
aroub
  • aroub
Oh well :/ Thanks everyone! :)

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