Here's the question you clicked on:
cwrw238
Find f' in terms of g' if f(x) = g(x + g(a)).
f'(x)=g'(x+g(a))*(1+0)=g'(x+g(a))
unless I'm doing something wrong.
i'm studying calculus at the moment i have a mental block with this one.
lol this is one of those questions that looks too easy to be true, but I think that is the answer.
if a is a constant, g(a) is a constant, so when you differentiate g(x+g(a)), then you just have the derivative of g: g'(x+g(a)), multiplied by the derivative of the inside, but: x'=1 g(a)=0, since g(a) is a constant, so all you have left is: g'(x+g(a))
yes derivaivte of x is 1 and that of a constant is 0 so it seems right...
http://brownsharpie.courtneygibbons.org/wp-content/comics/2006-12-18-chain-rule-baby.jpg
as you say its easy - just use chain rule ty