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cwrw238

  • 3 years ago

Find f' in terms of g' if f(x) = g(x + g(a)).

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  1. Agent47
    • 3 years ago
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    is a a constant?

  2. cwrw238
    • 3 years ago
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    yes

  3. Agent47
    • 3 years ago
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    f'(x)=g'(x+g(a))*(1+0)=g'(x+g(a))

  4. Agent47
    • 3 years ago
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    unless I'm doing something wrong.

  5. cwrw238
    • 3 years ago
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    i'm studying calculus at the moment i have a mental block with this one.

  6. Agent47
    • 3 years ago
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    lol this is one of those questions that looks too easy to be true, but I think that is the answer.

  7. Agent47
    • 3 years ago
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    if a is a constant, g(a) is a constant, so when you differentiate g(x+g(a)), then you just have the derivative of g: g'(x+g(a)), multiplied by the derivative of the inside, but: x'=1 g(a)=0, since g(a) is a constant, so all you have left is: g'(x+g(a))

  8. cwrw238
    • 3 years ago
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    yes derivaivte of x is 1 and that of a constant is 0 so it seems right...

  9. Agent47
    • 3 years ago
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    http://brownsharpie.courtneygibbons.org/wp-content/comics/2006-12-18-chain-rule-baby.jpg

  10. cwrw238
    • 3 years ago
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    lol! - like that one

  11. cwrw238
    • 3 years ago
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    as you say its easy - just use chain rule ty

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