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cwrw238 Group Title

Find f' in terms of g' if f(x) = g(x + g(a)).

  • one year ago
  • one year ago

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  1. Agent47 Group Title
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    is a a constant?

    • one year ago
  2. cwrw238 Group Title
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    yes

    • one year ago
  3. Agent47 Group Title
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    f'(x)=g'(x+g(a))*(1+0)=g'(x+g(a))

    • one year ago
  4. Agent47 Group Title
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    unless I'm doing something wrong.

    • one year ago
  5. cwrw238 Group Title
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    i'm studying calculus at the moment i have a mental block with this one.

    • one year ago
  6. Agent47 Group Title
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    lol this is one of those questions that looks too easy to be true, but I think that is the answer.

    • one year ago
  7. Agent47 Group Title
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    if a is a constant, g(a) is a constant, so when you differentiate g(x+g(a)), then you just have the derivative of g: g'(x+g(a)), multiplied by the derivative of the inside, but: x'=1 g(a)=0, since g(a) is a constant, so all you have left is: g'(x+g(a))

    • one year ago
  8. cwrw238 Group Title
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    yes derivaivte of x is 1 and that of a constant is 0 so it seems right...

    • one year ago
  9. Agent47 Group Title
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    http://brownsharpie.courtneygibbons.org/wp-content/comics/2006-12-18-chain-rule-baby.jpg

    • one year ago
  10. cwrw238 Group Title
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    lol! - like that one

    • one year ago
  11. cwrw238 Group Title
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    as you say its easy - just use chain rule ty

    • one year ago
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