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Charmi

Round off the following numbers to two significant digits. (a) 7.8361 (b) 85.51 (c) 2.85 (d) 9.865 (e) 4.67 (f) 2.75 (g) 6.750 (h) 490.0 (i) 0.006 070 (j) 648 700 (k) 704 (l) 0.599 0 (m) 435 (n) 0.000 16 (o) 0.032 45 (p) 6 807 (q) 0.000 053 (r) 0.070 40 (s) 68 (t) 0.080 5

  • one year ago
  • one year ago

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  1. Charmi
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    someone tell me how to do this

    • one year ago
  2. Denebel
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    http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch1/sigfigs.html

    • one year ago
  3. Agentjamesbond007
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    2 significant digits means x.xx (2 numbers after the decimal point; even if it is a while number). Simply round from the numbers right to left and stop after the 3rd digit after the decimal place. Example: rounding 3.7456 would be 3.75

    • one year ago
  4. Charmi
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    what abt 4 significant digits

    • one year ago
  5. Agentjamesbond007
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    Then, you'll need to have 4 digits after the decimal place. The same would be applied, but if say you need to round the number 5, it would be 5.0000 Significant digits (significant figures) are usually used for noting accuracy.

    • one year ago
  6. Charmi
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    oh ok thanks

    • one year ago
  7. Agentjamesbond007
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    You're Welcome!

    • one year ago
  8. Charmi
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    do you kno how to do scientific notations as well

    • one year ago
  9. Charmi
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    if you do, can you show me how please

    • one year ago
  10. nanaheads
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    I do

    • one year ago
  11. Charmi
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    how do you do it

    • one year ago
  12. Charmi
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    can you giv me an example

    • one year ago
  13. Agentjamesbond007
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    Scientific notation is basically getting a very big (or small) number, starting from the end (if big) or beginning (if small [decimal]), and count the place values from the initial point to a decimal point after the number. example: 440000 4.4x10^5 Here, you need to put an imaginary decimal point at the end of the number and shift it until you get the number 4.4. Count the place values and that's your x10 exponent. works the same way in a very small number 0.00002 2.0x10^-5

    • one year ago
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