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oholmes Group Title

(GEOMETRY, HELP PLEASE) Write the equation of the line with a slope of 3/7 passing through the point (9 -2)

  • one year ago
  • one year ago

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  1. Chlorophyll Group Title
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    Show me the slope form ....?

    • one year ago
  2. ParthKohli Group Title
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    \[y - y_1 = m(x - x_1) \]Here,\[m = {3 \over 7} \\ y_1 = -2\\x_1 = 9\]

    • one year ago
  3. oholmes Group Title
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    what is x?

    • one year ago
  4. oholmes Group Title
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    I got y=3/7x-2

    • one year ago
  5. hal_stirrup Group Title
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    hi

    • one year ago
  6. oholmes Group Title
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    hi

    • one year ago
  7. hal_stirrup Group Title
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    did you get it

    • one year ago
  8. CliffSedge Group Title
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    \[y=mx+b, y=-2, x=9, m=3/7\] Solve for b.

    • one year ago
  9. ParthKohli Group Title
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    Leave \(x\) and \(y\) just like \(x\) and \(y\).

    • one year ago
  10. oholmes Group Title
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    ok

    • one year ago
  11. oholmes Group Title
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    I got y=3/7x-2

    • one year ago
  12. CliffSedge Group Title
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    \[-2=\frac{3}{7}(9)+b, b=?\] And you got b=-2?

    • one year ago
  13. oholmes Group Title
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    9?

    • one year ago
  14. oholmes Group Title
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    @CliffSedge

    • one year ago
  15. CliffSedge Group Title
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    You can also use the equation Parth gave: \[y−y_1=m(x−x_1) \rightarrow y−(-2)=\frac{3}{7}(x−(9))\]

    • one year ago
  16. CliffSedge Group Title
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    Assuming you've studied algebra before, this should look familiar.

    • one year ago
  17. oholmes Group Title
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    2x-9= -3/7

    • one year ago
  18. CliffSedge Group Title
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    Ok, let's back way up then. The point is (9, -2) which means that at a particular point on the line, x=9, and y=-2. The slope is 3/7 which means from any point on the line, you can go up 3 units then to the right 7 units and find another point on the line.

    • one year ago
  19. CliffSedge Group Title
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    An equation of the line will be such that you can take the x and y coordinates from any point on the line and put them into the equation and make it a true statement. The slope is found by dividing the difference between the y coordinates of two points by the difference between the x coordinates of those two points (rise-over-run).

    • one year ago
  20. oholmes Group Title
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    This time is got 3x-7y=41

    • one year ago
  21. oholmes Group Title
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    • one year ago
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  22. oholmes Group Title
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    quick question, what type of triangle is RST?

    • one year ago
  23. CliffSedge Group Title
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    That looks better. You can test it by putting in the x and y coordinates from your point and seeing if it makes the statement true. i.e. 3(9)-7(-2)=?

    • one year ago
  24. oholmes Group Title
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    41

    • one year ago
  25. oholmes Group Title
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    Okay great! thank you

    • one year ago
  26. CliffSedge Group Title
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    Good, then the equation is true. For triangle RST, do you know how to measure the sides using the distance formula (i.e. the pythagorean theorem)? As a hint, notice the symmetry and how the sides RS and RT look to be the same length.

    • one year ago
  27. oholmes Group Title
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    is it isoscles?

    • one year ago
  28. CliffSedge Group Title
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    That would be a good guess. I'd probably still measure to make sure it wasn't equilateral. Can you see how long segment ST is?

    • one year ago
  29. oholmes Group Title
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    I cant tell

    • one year ago
  30. CliffSedge Group Title
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    The coordinates of points S and T are given. S is at (-4,7) and T is at (4,7). They are both at the height y=7, so it is a straight horizontal like going from x=-4 to x=4. How far is that?

    • one year ago
  31. oholmes Group Title
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    I got isoscles. I check

    • one year ago
  32. CliffSedge Group Title
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    Ok, I just want to make sure you know how to handle these questions in general in case you see a similar problem, that isn't so easy to solve.

    • one year ago
  33. CliffSedge Group Title
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    There are particular skills and knowledge that these questions are testing from you. It is important that you have these basic skills proficiently so that you can move on to more difficult problems.

    • one year ago
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