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shelovespiano Group Title

Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers. (2x^4 * y^(-4/5))^3(8y^2)^(2/3) I try to post it in equation form too.

  • one year ago
  • one year ago

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  1. J-Monstur Group Title
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    Could you draw it out?

    • one year ago
  2. shelovespiano Group Title
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    \[(2x^4y^\frac{ -4 }{ 5 })^3(8y^2)^\frac{ 2 }{ 3 }\]

    • one year ago
  3. Denebel Group Title
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    if it was \[(a ^{4})^{3}\] What have you learned to do with the exponents?

    • one year ago
  4. shelovespiano Group Title
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    Multiply 4 and 3, right?

    • one year ago
  5. Denebel Group Title
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    Yes, what if it was \[(4a ^{4})^{3}\] ?

    • one year ago
  6. shelovespiano Group Title
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    4 to the third times a to the 12

    • one year ago
  7. Denebel Group Title
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    Yes, what happens with \[(8y ^{2})^{2/3}\] ?

    • one year ago
  8. shelovespiano Group Title
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    \[8^\frac{ 2 }{ 3 }y ^\frac{ 4 }{ 3 }\]

    • one year ago
  9. Denebel Group Title
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    Ok, so which part do you have trouble with?

    • one year ago
  10. shelovespiano Group Title
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    Well, the answer in the back of the book is 14, and no matter what I do, i can't get 14! I'll take a picture of my work real quick and maybe you can see what I did then?

    • one year ago
  11. Denebel Group Title
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    Sure

    • one year ago
  12. helder_edwin Group Title
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    \[ \large (2x^4y^{-4/5})^3(8y^2)^{2/3}=2^3x^{4\times3}y^{-4/5\times3} 8^{2/3}y^{2\times2/3} \]

    • one year ago
  13. helder_edwin Group Title
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    \[ \large 8x^{12}y^{-12/5}8^{2/3}y^{4/3} \]

    • one year ago
  14. helder_edwin Group Title
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    \[ \large =8^{1+2/3}x^{12}y^{4/3-12/5}=8^{5/3}x^{12}y^{-16/15} \]

    • one year ago
  15. lopus Group Title
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    |dw:1347151652056:dw|

    • one year ago
  16. lopus Group Title
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    \[2x^{12}*\frac{ 8 }{ y}\]

    • one year ago
  17. shelovespiano Group Title
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    Here's what I have... I've just tried a few times and I'm really having difficulty. This is my most recent bit.

    • one year ago
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  18. helder_edwin Group Title
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    \[ \large =2^5x^{12}y^{-16/15} \]

    • one year ago
  19. shelovespiano Group Title
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    According to the back of the book, the answer is \[(32x^\frac{ 12 }{ 1 })/(y^ \frac{ 16 }{ 15 })\]

    • one year ago
  20. shelovespiano Group Title
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    I just don't have an idea of how to get it.

    • one year ago
  21. helder_edwin Group Title
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    \[ \large \frac{32x^{12}}{y^{16/15}} \] 2^5=32

    • one year ago
  22. lopus Group Title
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    |dw:1347152276782:dw|

    • one year ago
  23. Denebel Group Title
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    You broke down your y's by saying \[y ^{4/3}= y \sqrt[3]{y}\] and such...

    • one year ago
  24. lopus Group Title
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    \[y ^{-1}=\frac{ 1 }{ y }\]

    • one year ago
  25. Denebel Group Title
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    |dw:1347152573807:dw|

    • one year ago
  26. shelovespiano Group Title
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    ok, thanks everyone! i have a better understanding now.

    • one year ago
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