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shelovespiano
Group Title
Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers.
(2x^4 * y^(4/5))^3(8y^2)^(2/3)
I try to post it in equation form too.
 one year ago
 one year ago
shelovespiano Group Title
Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers. (2x^4 * y^(4/5))^3(8y^2)^(2/3) I try to post it in equation form too.
 one year ago
 one year ago

This Question is Closed

JMonstur Group TitleBest ResponseYou've already chosen the best response.0
Could you draw it out?
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
\[(2x^4y^\frac{ 4 }{ 5 })^3(8y^2)^\frac{ 2 }{ 3 }\]
 one year ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
if it was \[(a ^{4})^{3}\] What have you learned to do with the exponents?
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
Multiply 4 and 3, right?
 one year ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Yes, what if it was \[(4a ^{4})^{3}\] ?
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
4 to the third times a to the 12
 one year ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Yes, what happens with \[(8y ^{2})^{2/3}\] ?
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
\[8^\frac{ 2 }{ 3 }y ^\frac{ 4 }{ 3 }\]
 one year ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Ok, so which part do you have trouble with?
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
Well, the answer in the back of the book is 14, and no matter what I do, i can't get 14! I'll take a picture of my work real quick and maybe you can see what I did then?
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large (2x^4y^{4/5})^3(8y^2)^{2/3}=2^3x^{4\times3}y^{4/5\times3} 8^{2/3}y^{2\times2/3} \]
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large 8x^{12}y^{12/5}8^{2/3}y^{4/3} \]
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large =8^{1+2/3}x^{12}y^{4/312/5}=8^{5/3}x^{12}y^{16/15} \]
 one year ago

lopus Group TitleBest ResponseYou've already chosen the best response.0
dw:1347151652056:dw
 one year ago

lopus Group TitleBest ResponseYou've already chosen the best response.0
\[2x^{12}*\frac{ 8 }{ y}\]
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
Here's what I have... I've just tried a few times and I'm really having difficulty. This is my most recent bit.
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large =2^5x^{12}y^{16/15} \]
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
According to the back of the book, the answer is \[(32x^\frac{ 12 }{ 1 })/(y^ \frac{ 16 }{ 15 })\]
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
I just don't have an idea of how to get it.
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large \frac{32x^{12}}{y^{16/15}} \] 2^5=32
 one year ago

lopus Group TitleBest ResponseYou've already chosen the best response.0
dw:1347152276782:dw
 one year ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
You broke down your y's by saying \[y ^{4/3}= y \sqrt[3]{y}\] and such...
 one year ago

lopus Group TitleBest ResponseYou've already chosen the best response.0
\[y ^{1}=\frac{ 1 }{ y }\]
 one year ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
dw:1347152573807:dw
 one year ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
ok, thanks everyone! i have a better understanding now.
 one year ago
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