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 2 years ago
Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers.
(2x^4 * y^(4/5))^3(8y^2)^(2/3)
I try to post it in equation form too.
 2 years ago
Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers. (2x^4 * y^(4/5))^3(8y^2)^(2/3) I try to post it in equation form too.

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JMonstur
 2 years ago
Best ResponseYou've already chosen the best response.0Could you draw it out?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0\[(2x^4y^\frac{ 4 }{ 5 })^3(8y^2)^\frac{ 2 }{ 3 }\]

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1if it was \[(a ^{4})^{3}\] What have you learned to do with the exponents?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0Multiply 4 and 3, right?

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, what if it was \[(4a ^{4})^{3}\] ?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.04 to the third times a to the 12

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, what happens with \[(8y ^{2})^{2/3}\] ?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0\[8^\frac{ 2 }{ 3 }y ^\frac{ 4 }{ 3 }\]

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1Ok, so which part do you have trouble with?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0Well, the answer in the back of the book is 14, and no matter what I do, i can't get 14! I'll take a picture of my work real quick and maybe you can see what I did then?

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large (2x^4y^{4/5})^3(8y^2)^{2/3}=2^3x^{4\times3}y^{4/5\times3} 8^{2/3}y^{2\times2/3} \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large 8x^{12}y^{12/5}8^{2/3}y^{4/3} \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large =8^{1+2/3}x^{12}y^{4/312/5}=8^{5/3}x^{12}y^{16/15} \]

lopus
 2 years ago
Best ResponseYou've already chosen the best response.0\[2x^{12}*\frac{ 8 }{ y}\]

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0Here's what I have... I've just tried a few times and I'm really having difficulty. This is my most recent bit.

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large =2^5x^{12}y^{16/15} \]

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0According to the back of the book, the answer is \[(32x^\frac{ 12 }{ 1 })/(y^ \frac{ 16 }{ 15 })\]

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0I just don't have an idea of how to get it.

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large \frac{32x^{12}}{y^{16/15}} \] 2^5=32

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1You broke down your y's by saying \[y ^{4/3}= y \sqrt[3]{y}\] and such...

lopus
 2 years ago
Best ResponseYou've already chosen the best response.0\[y ^{1}=\frac{ 1 }{ y }\]

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0ok, thanks everyone! i have a better understanding now.
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