A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers.
(2x^4 * y^(4/5))^3(8y^2)^(2/3)
I try to post it in equation form too.
 2 years ago
Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers. (2x^4 * y^(4/5))^3(8y^2)^(2/3) I try to post it in equation form too.

This Question is Closed

JMonstur
 2 years ago
Best ResponseYou've already chosen the best response.0Could you draw it out?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0\[(2x^4y^\frac{ 4 }{ 5 })^3(8y^2)^\frac{ 2 }{ 3 }\]

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1if it was \[(a ^{4})^{3}\] What have you learned to do with the exponents?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0Multiply 4 and 3, right?

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, what if it was \[(4a ^{4})^{3}\] ?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.04 to the third times a to the 12

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, what happens with \[(8y ^{2})^{2/3}\] ?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0\[8^\frac{ 2 }{ 3 }y ^\frac{ 4 }{ 3 }\]

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1Ok, so which part do you have trouble with?

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0Well, the answer in the back of the book is 14, and no matter what I do, i can't get 14! I'll take a picture of my work real quick and maybe you can see what I did then?

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large (2x^4y^{4/5})^3(8y^2)^{2/3}=2^3x^{4\times3}y^{4/5\times3} 8^{2/3}y^{2\times2/3} \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large 8x^{12}y^{12/5}8^{2/3}y^{4/3} \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large =8^{1+2/3}x^{12}y^{4/312/5}=8^{5/3}x^{12}y^{16/15} \]

lopus
 2 years ago
Best ResponseYou've already chosen the best response.0\[2x^{12}*\frac{ 8 }{ y}\]

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0Here's what I have... I've just tried a few times and I'm really having difficulty. This is my most recent bit.

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large =2^5x^{12}y^{16/15} \]

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0According to the back of the book, the answer is \[(32x^\frac{ 12 }{ 1 })/(y^ \frac{ 16 }{ 15 })\]

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0I just don't have an idea of how to get it.

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \large \frac{32x^{12}}{y^{16/15}} \] 2^5=32

Denebel
 2 years ago
Best ResponseYou've already chosen the best response.1You broke down your y's by saying \[y ^{4/3}= y \sqrt[3]{y}\] and such...

lopus
 2 years ago
Best ResponseYou've already chosen the best response.0\[y ^{1}=\frac{ 1 }{ y }\]

shelovespiano
 2 years ago
Best ResponseYou've already chosen the best response.0ok, thanks everyone! i have a better understanding now.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.