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shelovespiano
Group Title
Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers.
(2x^4 * y^(4/5))^3(8y^2)^(2/3)
I try to post it in equation form too.
 2 years ago
 2 years ago
shelovespiano Group Title
Simplify the expression and eliminate any negative exponents, assuming that all letters denote positive numbers. (2x^4 * y^(4/5))^3(8y^2)^(2/3) I try to post it in equation form too.
 2 years ago
 2 years ago

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JMonstur Group TitleBest ResponseYou've already chosen the best response.0
Could you draw it out?
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
\[(2x^4y^\frac{ 4 }{ 5 })^3(8y^2)^\frac{ 2 }{ 3 }\]
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
if it was \[(a ^{4})^{3}\] What have you learned to do with the exponents?
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
Multiply 4 and 3, right?
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Yes, what if it was \[(4a ^{4})^{3}\] ?
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
4 to the third times a to the 12
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Yes, what happens with \[(8y ^{2})^{2/3}\] ?
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
\[8^\frac{ 2 }{ 3 }y ^\frac{ 4 }{ 3 }\]
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Ok, so which part do you have trouble with?
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
Well, the answer in the back of the book is 14, and no matter what I do, i can't get 14! I'll take a picture of my work real quick and maybe you can see what I did then?
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large (2x^4y^{4/5})^3(8y^2)^{2/3}=2^3x^{4\times3}y^{4/5\times3} 8^{2/3}y^{2\times2/3} \]
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large 8x^{12}y^{12/5}8^{2/3}y^{4/3} \]
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large =8^{1+2/3}x^{12}y^{4/312/5}=8^{5/3}x^{12}y^{16/15} \]
 2 years ago

lopus Group TitleBest ResponseYou've already chosen the best response.0
dw:1347151652056:dw
 2 years ago

lopus Group TitleBest ResponseYou've already chosen the best response.0
\[2x^{12}*\frac{ 8 }{ y}\]
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
Here's what I have... I've just tried a few times and I'm really having difficulty. This is my most recent bit.
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large =2^5x^{12}y^{16/15} \]
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
According to the back of the book, the answer is \[(32x^\frac{ 12 }{ 1 })/(y^ \frac{ 16 }{ 15 })\]
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
I just don't have an idea of how to get it.
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
\[ \large \frac{32x^{12}}{y^{16/15}} \] 2^5=32
 2 years ago

lopus Group TitleBest ResponseYou've already chosen the best response.0
dw:1347152276782:dw
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
You broke down your y's by saying \[y ^{4/3}= y \sqrt[3]{y}\] and such...
 2 years ago

lopus Group TitleBest ResponseYou've already chosen the best response.0
\[y ^{1}=\frac{ 1 }{ y }\]
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
dw:1347152573807:dw
 2 years ago

shelovespiano Group TitleBest ResponseYou've already chosen the best response.0
ok, thanks everyone! i have a better understanding now.
 2 years ago
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