anonymous
  • anonymous
How to solve: log(x+2) + log(x-1) = 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Hint: loga + logb = log(a/b)
anonymous
  • anonymous
Does it help?
anonymous
  • anonymous
Hmm give me a sec

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anonymous
  • anonymous
Not really :$ the answer is 3 and that just gives me a quadratic formula
anonymous
  • anonymous
Are they base 10?
anonymous
  • anonymous
yes
anonymous
  • anonymous
I assume
anonymous
  • anonymous
1=log10
anonymous
  • anonymous
So, log(x+2) + log(x-1) = 1 log{(x+2)(x-1)} = log10
anonymous
  • anonymous
That may help
anonymous
  • anonymous
Do you know what to do when both 2 sides have the same base?
anonymous
  • anonymous
I don't think so (chlorophyll)
anonymous
  • anonymous
So learn the rule, both logs will be CANCELLED out :)
anonymous
  • anonymous
really? okay, but then I'm still confused :$
anonymous
  • anonymous
okay, so it would still be (x+2)(x-1) = 10
anonymous
  • anonymous
x^2 +x -2 = 10
anonymous
  • anonymous
or x^2+x-12 actually
anonymous
  • anonymous
=0
anonymous
  • anonymous
... solve the quadratic equation?
anonymous
  • anonymous
and then is the positive root just my answer?
anonymous
  • anonymous
Perfect! I'm waiting for your x = ...?
anonymous
  • anonymous
3
anonymous
  • anonymous
Wow, why's so fast! Hmm...
anonymous
  • anonymous
Anyway, correct!
anonymous
  • anonymous
Questions?
anonymous
  • anonymous
um no thanks :) will try that with the next question now!

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