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Cutiepo0

How to solve: log(x+2) + log(x-1) = 1

  • one year ago
  • one year ago

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  1. sauravshakya
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    Hint: loga + logb = log(a/b)

    • one year ago
  2. sauravshakya
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    Does it help?

    • one year ago
  3. Cutiepo0
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    Hmm give me a sec

    • one year ago
  4. Cutiepo0
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    Not really :$ the answer is 3 and that just gives me a quadratic formula

    • one year ago
  5. Chlorophyll
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    Are they base 10?

    • one year ago
  6. Cutiepo0
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    yes

    • one year ago
  7. Cutiepo0
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    I assume

    • one year ago
  8. sauravshakya
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    1=log10

    • one year ago
  9. sauravshakya
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    So, log(x+2) + log(x-1) = 1 log{(x+2)(x-1)} = log10

    • one year ago
  10. sauravshakya
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    That may help

    • one year ago
  11. Chlorophyll
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    Do you know what to do when both 2 sides have the same base?

    • one year ago
  12. Cutiepo0
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    I don't think so (chlorophyll)

    • one year ago
  13. Chlorophyll
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    So learn the rule, both logs will be CANCELLED out :)

    • one year ago
  14. Cutiepo0
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    really? okay, but then I'm still confused :$

    • one year ago
  15. Cutiepo0
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    okay, so it would still be (x+2)(x-1) = 10

    • one year ago
  16. Cutiepo0
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    x^2 +x -2 = 10

    • one year ago
  17. Cutiepo0
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    or x^2+x-12 actually

    • one year ago
  18. Cutiepo0
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    =0

    • one year ago
  19. Cutiepo0
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    ... solve the quadratic equation?

    • one year ago
  20. Cutiepo0
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    and then is the positive root just my answer?

    • one year ago
  21. Chlorophyll
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    Perfect! I'm waiting for your x = ...?

    • one year ago
  22. Cutiepo0
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    3

    • one year ago
  23. Chlorophyll
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    Wow, why's so fast! Hmm...

    • one year ago
  24. Chlorophyll
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    Anyway, correct!

    • one year ago
  25. Chlorophyll
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    Questions?

    • one year ago
  26. Cutiepo0
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    um no thanks :) will try that with the next question now!

    • one year ago
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