Cutiepo0
How to solve:
log(x+2) + log(x1) = 1



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sauravshakya
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Hint: loga + logb = log(a/b)

sauravshakya
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Does it help?

Cutiepo0
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Hmm give me a sec

Cutiepo0
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Not really :$ the answer is 3 and that just gives me a quadratic formula

Chlorophyll
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Are they base 10?

Cutiepo0
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yes

Cutiepo0
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I assume

sauravshakya
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1=log10

sauravshakya
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So, log(x+2) + log(x1) = 1
log{(x+2)(x1)} = log10

sauravshakya
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That may help

Chlorophyll
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Do you know what to do when both 2 sides have the same base?

Cutiepo0
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I don't think so (chlorophyll)

Chlorophyll
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So learn the rule, both logs will be CANCELLED out :)

Cutiepo0
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really? okay, but then I'm still confused :$

Cutiepo0
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okay, so it would still be (x+2)(x1) = 10

Cutiepo0
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x^2 +x 2 = 10

Cutiepo0
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or x^2+x12 actually

Cutiepo0
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=0

Cutiepo0
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... solve the quadratic equation?

Cutiepo0
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and then is the positive root just my answer?

Chlorophyll
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Perfect! I'm waiting for your x = ...?

Cutiepo0
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3

Chlorophyll
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Wow, why's so fast!
Hmm...

Chlorophyll
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Anyway, correct!

Chlorophyll
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Questions?

Cutiepo0
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um no thanks :) will try that with the next question now!