lgbasallote
  • lgbasallote
LGBARIDDLE!!! 1 + 2 = 3 1 + 4 = 5 3 + 2 = 5 1 + 1 = 3 so what's 2 + 5?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
20 bucks natural log and hyperbolic secant are in the answer.... :P
hartnn
  • hartnn
are u sure question is 2+5 and not 1+5 ??
lgbasallote
  • lgbasallote
of course im sure...im the one who made it lol

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hartnn
  • hartnn
because i got 1+5 ....
anonymous
  • anonymous
I'm getting 5, but i'm not sure xD
lgbasallote
  • lgbasallote
why would you say 5??
anonymous
  • anonymous
1+2=3, so 1=1 1+4=5, so 1=1 3+2=5, so 3=3 1+1=3, so 1=2 3+(1=2)=5, so 4=5 so 2+5 = (1+4) = 5 idk if this makes any sense, but i'm assuming 7 isn't the answer here haha xD
lgbasallote
  • lgbasallote
this isn't programming.... o.O
anonymous
  • anonymous
oh... i didn't know there was a theme to the riddle xD
lgbasallote
  • lgbasallote
well...it is in the math section...
anonymous
  • anonymous
hahaha touche sir xD
hartnn
  • hartnn
if u give me 3+3 or 4+4 i can give u 2+5 all these 3 are equal.
lgbasallote
  • lgbasallote
not really...
ParthKohli
  • ParthKohli
I'm cool with the first three, but the fourth messes it up. :|
anonymous
  • anonymous
6
lgbasallote
  • lgbasallote
vintage lgbariddles
lgbasallote
  • lgbasallote
@Omniscience no
anonymous
  • anonymous
then its another ambiguous riddle :P
hartnn
  • hartnn
any hint?
ParthKohli
  • ParthKohli
2 + 5 = 7!!!
lgbasallote
  • lgbasallote
@hartnn addition
hartnn
  • hartnn
i did add those...1st i formed equation, a+b=c,a+d=e ....(a-1,b=2,....) but could not get b+e as single 'letter' ....am i on right track ?
anonymous
  • anonymous
8
sasogeek
  • sasogeek
does the usual algebraic rules apply? eg. a+b=c => a=c-b ?
UnkleRhaukus
  • UnkleRhaukus
9
lgbasallote
  • lgbasallote
still no
sasogeek
  • sasogeek
i have a feeling the answer is a decimal -_-
lgbasallote
  • lgbasallote
nope. it's whole
sasogeek
  • sasogeek
well you didn't answer my earlier question lol
lgbasallote
  • lgbasallote
i dont tink it's relevant
sasogeek
  • sasogeek
i think it is, i wanted to try something which might help so i need that info :) at least i have a right to know if that's possible or not :P

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