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apple_pi

  • 3 years ago

prove trig identity...

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  1. apple_pi
    • 3 years ago
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    \[\tan \theta=\frac{ \sin 2\theta }{ 1+\cos2\theta }\]

  2. hartnn
    • 3 years ago
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    write sin 2theta = 2sin theta cos theta and 1+cos 2 theta = 2 cos^2 theta.

  3. ParthKohli
    • 3 years ago
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    We already know that,\[\tan = {\sin \over \cos}\]and if you try to simplify\[2\sin\theta \cos\theta \over 2\cos^2\theta\], then you get \(\large{\sin\theta\over \cos\theta}\)

  4. apple_pi
    • 3 years ago
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    Ahh. ok thanks

  5. ParthKohli
    • 3 years ago
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    You're welcome :)

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