Omniscience
If a random selection is made from 1,2,3,4,5,6 where the digits cannot be repeated, find the probability that the number selected is greater than 4500
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apple_pi
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how many numbers are selected? 4?
Omniscience
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yeah 4 digits; i forgot to mention that sorry
apple_pi
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well if > 4500, there are two cases:
1: first number = 4, second = 5
2: first number > 4
Omniscience
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isnt the first case 4,5 ,6?
Ishaan94
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2C1*6P4 + 2C1*5P2?
Omniscience
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nope
Ishaan94
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Are you sure?
Omniscience
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yes itcant be that high lol
the probability is 2/5
and from what you got is 14440/360
Omniscience
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wait from what you got is 760/360; still not right
IsraelYkb
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(12*6)/(6*5*4*3)
IsraelYkb
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mine 72/360.
Omniscience
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i got that as well; still not right
Ishaan94
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I am sorry. I blew it :(
First Case. When first digit is greater than 4 i.e {5,6}.
2C1*(5*4*3)
Second Case. When first digit is 4, and second is 5.
4*3
IsraelYkb
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@Omniscience 2/5 is not right?
Omniscience
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72/360 = 1/5
still not right..
Ishaan94
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Second Case should be 2*4*3 as the second could be 6 also. I believe I have got the answer.
Ishaan94
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... second digit* could be ...
Omniscience
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yes ishaan got it. thanks
RadEn
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all case :
|dw:1347236931812:dw|
IsraelYkb
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|dw:1347266631816:dw|
IsraelYkb
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2*(12)+120
IsraelYkb
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I GOT IT!!!!!!!!!!!!!!!!
IsraelYkb
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144 ways out of 360
RadEn
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why, 2*12?
IsraelYkb
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oh....|dw:1347267287282:dw|
that's why
IsraelYkb
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that's 1*2*4*3
same as 2*12
RadEn
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oh, yea... i am forget that |4|6|...|...| should can be selected ... lol
thanks @IsraelYkb
IsraelYkb
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and using 5 and 6 it's very easy it's just 2*5*4*3
RadEn
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yea, that's i know...