If a random selection is made from 1,2,3,4,5,6 where the digits cannot be repeated, find the probability that the number selected is greater than 4500

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If a random selection is made from 1,2,3,4,5,6 where the digits cannot be repeated, find the probability that the number selected is greater than 4500

Mathematics
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how many numbers are selected? 4?
yeah 4 digits; i forgot to mention that sorry
well if > 4500, there are two cases: 1: first number = 4, second = 5 2: first number > 4

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isnt the first case 4,5 ,6?
2C1*6P4 + 2C1*5P2?
nope
Are you sure?
yes itcant be that high lol the probability is 2/5 and from what you got is 14440/360
wait from what you got is 760/360; still not right
(12*6)/(6*5*4*3)
mine 72/360.
i got that as well; still not right
I am sorry. I blew it :( First Case. When first digit is greater than 4 i.e {5,6}. 2C1*(5*4*3) Second Case. When first digit is 4, and second is 5. 4*3
@Omniscience 2/5 is not right?
72/360 = 1/5 still not right..
Second Case should be 2*4*3 as the second could be 6 also. I believe I have got the answer.
... second digit* could be ...
yes ishaan got it. thanks
all case : |dw:1347236931812:dw|
|dw:1347266631816:dw|
2*(12)+120
I GOT IT!!!!!!!!!!!!!!!!
144 ways out of 360
why, 2*12?
oh....|dw:1347267287282:dw| that's why
that's 1*2*4*3 same as 2*12
oh, yea... i am forget that |4|6|...|...| should can be selected ... lol thanks @IsraelYkb
and using 5 and 6 it's very easy it's just 2*5*4*3
yea, that's i know...

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