Please answer this, because I am suffering horrible calculus-related feelings of self doubt, shattered dreams, and existential dread.
Suppose that 2J of work is needed to stretch a spring from its natural length of 30cm to a length of 42cm.
(a) I've already solved this, and every time someone else has posted both a and b, they only answer a and for some reason ignore that b exists.
(b) How far beyond its natural length will a force of 30N keep the spring stretched?
Hooke's Law: F = kx
k = 138.9
The answer is 10.8cm.
Explain step by step because I feel more stupid the longer I spend on these godforsaken problems. Explain in integral form.
Please.

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whats question a?

isnt it just \(F=kx\) for part b ?

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