cupcake_queen
write a function rule for the table



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cupcake_queen
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dw:1347209929796:dw

jasonxx
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y3=(53)/(20)*(x0)
y3=2/2*x
y3=x and
y=x+3

jasonxx
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@cupcake_queen clear?

cupcake_queen
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u have to use the letters on the table

jasonxx
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y=f(x)

jasonxx
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f(x)=x+3

jasonxx
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does that help you amy?

cupcake_queen
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oh ok

cupcake_queen
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i thought y was the output

amistre64
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so, what exactly is the nature of the report abuse?

cupcake_queen
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u should message me about that