Mandy86
Solve the equation in quadratic formula!
2x^29x2=0



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Mandy86
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i got 9\[9\pm \sqrt{65}/4\]

JadeEyes
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Then \[x = \frac{ b \pm \sqrt{b ^{2}  4ac } }{2a}\]
Where a = 2 b = 9 c = 2

Mandy86
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i know how to do that
i just got confused at the end

JadeEyes
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\[x = \frac{ 9\pm \sqrt{97}}{4}\]

JadeEyes
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c = 2 .. sorry my mistake..!

Mandy86
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yeah it should be \[\sqrt{65}\] not\[\sqrt{97}\]

JadeEyes
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its \[\sqrt{97}\]
since b^2  4ac = (9^2)  (4x 2 x 2) = 81  (16) = 97

Mandy86
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ur right i subtracted instead of add. thank you

JadeEyes
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Ur Welcome..!! (:

JadeEyes
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So you got the answer?

Mandy86
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yes