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Mandy86 Group Title

Solve the equation in quadratic formula! 2x^2-9x-2=0

  • 2 years ago
  • 2 years ago

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  1. Mandy86 Group Title
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    i got 9\[9\pm \sqrt{65}/4\]

    • 2 years ago
  2. JadeEyes Group Title
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    Then \[x = \frac{ -b \pm \sqrt{b ^{2} - 4ac } }{2a}\] Where a = 2 b = -9 c = 2

    • 2 years ago
  3. Mandy86 Group Title
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    i know how to do that i just got confused at the end

    • 2 years ago
  4. JadeEyes Group Title
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    \[x = \frac{ 9\pm \sqrt{97}}{4}\]

    • 2 years ago
  5. JadeEyes Group Title
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    c = -2 .. sorry my mistake..!

    • 2 years ago
  6. Mandy86 Group Title
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    yeah it should be \[\sqrt{65}\] not\[\sqrt{97}\]

    • 2 years ago
  7. JadeEyes Group Title
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    its \[\sqrt{97}\] since b^2 - 4ac = (-9^2) - (4x 2 x -2) = 81 - (-16) = 97

    • 2 years ago
  8. Mandy86 Group Title
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    ur right i subtracted instead of add. thank you

    • 2 years ago
  9. JadeEyes Group Title
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    Ur Welcome..!! (:

    • 2 years ago
  10. JadeEyes Group Title
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    So you got the answer?

    • 2 years ago
  11. Mandy86 Group Title
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    yes

    • 2 years ago
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