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Solve the equation in quadratic formula! 2x^2-9x-2=0

Mathematics
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i got 9\[9\pm \sqrt{65}/4\]
Then \[x = \frac{ -b \pm \sqrt{b ^{2} - 4ac } }{2a}\] Where a = 2 b = -9 c = 2
i know how to do that i just got confused at the end

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Other answers:

\[x = \frac{ 9\pm \sqrt{97}}{4}\]
c = -2 .. sorry my mistake..!
yeah it should be \[\sqrt{65}\] not\[\sqrt{97}\]
its \[\sqrt{97}\] since b^2 - 4ac = (-9^2) - (4x 2 x -2) = 81 - (-16) = 97
ur right i subtracted instead of add. thank you
Ur Welcome..!! (:
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