anonymous
  • anonymous
pre-cal Find (a) sin a and cos B, (b) tan a and cot B, and (c) sec a and csc B.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1347217242148:dw|
anonymous
  • anonymous
since this is a right triangle, can you give me the length of the hypotenuse?
anonymous
  • anonymous
hello?

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anonymous
  • anonymous
meow?
anonymous
  • anonymous
so would i do the pythag. theorm?
anonymous
  • anonymous
yes....
anonymous
  • anonymous
what do i do after that?
anonymous
  • anonymous
do you know the definition o the trig functions? or better yet, the acronym: SOHCAHTOA: Sine = Opposite/Hypotenuse Cosine = Adjacent/Hypotenuse Tangent = Opposite/Adjacent
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok... so once you have the hypotenuse, you can determine the trig ratios for the angles that you want....
anonymous
  • anonymous
so... what do you have for the length of the hypotenuse?
anonymous
  • anonymous
\[\sqrt{34}\]
anonymous
  • anonymous
|dw:1347218499018:dw| now you can you determine the trig ratio's???
anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
yw...:)
anonymous
  • anonymous
@catgirl17 Do you want to post your result, so we can double check?
anonymous
  • anonymous
okay
anonymous
  • anonymous
a) \[3\sqrt{34}/34 \] \[5\sqrt{34}/34\]
anonymous
  • anonymous
a) the result should be the same: 3/ √ 34 ( 3√ 34/ 34 )
anonymous
  • anonymous
why?
anonymous
  • anonymous
b) 3/5 , 5/3 c) \[\sqrt{34}/5\] , \[\sqrt{34}/3\]
anonymous
  • anonymous
sinA = opp/ hyp = 3/√ 34 cosB = adj/ hyp = 3/√ 34
anonymous
  • anonymous
When you can fix your a) then go ahead fix b) and c)
anonymous
  • anonymous
b) 3/3, 3/3 c) \[\sqrt{34}/3\] \[\sqrt{34}/3\]
anonymous
  • anonymous
b) tanA = opp/ adj = 3/5
anonymous
  • anonymous
okay
anonymous
  • anonymous
C) secA = hyp/ adj = √ 34/5
anonymous
  • anonymous
okay
anonymous
  • anonymous
@catgirl17 That's the reason you need to volunteer post your working solution, so we can help you through the correct final result!

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