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spndsh Group TitleBest ResponseYou've already chosen the best response.0
Two forces of mag Ta=8 kips and Tb=15kips are applied as shown to a welded connection. determine the magnitudes of the forces Tc, and Td.
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
We need a picture...
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Well do you know what static equilibrium means for \(\Sigma \vec F\)?
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
yes. Now define the axes such that x is horizontal and y is vertical. What is Ta, Tb in component form?
 2 years ago

spndsh Group TitleBest ResponseYou've already chosen the best response.0
ta = (8, 0) tb=(15,0)
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
yes. Now, if the magnitude of \(\vec T_d=D\), then what are the components for Td? Also, let the mag of Tc = C. What are the comps for Tc?
 2 years ago

spndsh Group TitleBest ResponseYou've already chosen the best response.0
Td = (dcos140, dsin140) tc =(ccos270, csin270)
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
close. \(\vec T_d= D(\cos40, \sin40)\) and you're right about C. Can you simplify cos 270 and sin 270 though?
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Okay. Then if I have vectors Ta, Tb, Tc, Td, each with x and y components, do you agree that\[T_{ax}+T_{bx}+T_{cx}+T_{dx}=\Sigma F_x\] and \[T_{ay}+T_{by}+T_{cy}+T_{dy}=\Sigma \vec F_y\]? Because if you do, you can replace the known values and have 2 equations, 2 variables, which is solvable.
 2 years ago
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