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spndsh Group TitleBest ResponseYou've already chosen the best response.0
Two forces of mag Ta=8 kips and Tb=15kips are applied as shown to a welded connection. determine the magnitudes of the forces Tc, and Td.
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
We need a picture...
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Well do you know what static equilibrium means for \(\Sigma \vec F\)?
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
yes. Now define the axes such that x is horizontal and y is vertical. What is Ta, Tb in component form?
 one year ago

spndsh Group TitleBest ResponseYou've already chosen the best response.0
ta = (8, 0) tb=(15,0)
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
yes. Now, if the magnitude of \(\vec T_d=D\), then what are the components for Td? Also, let the mag of Tc = C. What are the comps for Tc?
 one year ago

spndsh Group TitleBest ResponseYou've already chosen the best response.0
Td = (dcos140, dsin140) tc =(ccos270, csin270)
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
close. \(\vec T_d= D(\cos40, \sin40)\) and you're right about C. Can you simplify cos 270 and sin 270 though?
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Okay. Then if I have vectors Ta, Tb, Tc, Td, each with x and y components, do you agree that\[T_{ax}+T_{bx}+T_{cx}+T_{dx}=\Sigma F_x\] and \[T_{ay}+T_{by}+T_{cy}+T_{dy}=\Sigma \vec F_y\]? Because if you do, you can replace the known values and have 2 equations, 2 variables, which is solvable.
 one year ago
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