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spndsh

  • 3 years ago

Static Equilibrium Problem

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  1. spndsh
    • 3 years ago
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    Two forces of mag Ta=8 kips and Tb=15kips are applied as shown to a welded connection. determine the magnitudes of the forces Tc, and Td.

  2. vf321
    • 3 years ago
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    We need a picture...

  3. spndsh
    • 3 years ago
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  4. vf321
    • 3 years ago
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    Well do you know what static equilibrium means for \(\Sigma \vec F\)?

  5. spndsh
    • 3 years ago
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    =0

  6. vf321
    • 3 years ago
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    yes. Now define the axes such that x is horizontal and y is vertical. What is Ta, Tb in component form?

  7. spndsh
    • 3 years ago
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    ta = (-8, 0) tb=(15,0)

  8. vf321
    • 3 years ago
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    yes. Now, if the magnitude of \(\vec T_d=D\), then what are the components for Td? Also, let the mag of Tc = C. What are the comps for Tc?

  9. spndsh
    • 3 years ago
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    Td = (dcos140, dsin140) tc =(ccos270, csin270)

  10. vf321
    • 3 years ago
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    close. \(\vec T_d= D(\cos40, -\sin40)\) and you're right about C. Can you simplify cos 270 and sin 270 though?

  11. spndsh
    • 3 years ago
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    c(0, -1)

  12. vf321
    • 3 years ago
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    Okay. Then if I have vectors Ta, Tb, Tc, Td, each with x and y components, do you agree that\[T_{ax}+T_{bx}+T_{cx}+T_{dx}=\Sigma F_x\] and \[T_{ay}+T_{by}+T_{cy}+T_{dy}=\Sigma \vec F_y\]? Because if you do, you can replace the known values and have 2 equations, 2 variables, which is solvable.

  13. spndsh
    • 3 years ago
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    thanks!

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