## vf321 Why is $$\Delta q = \lambda$$? Let's say I'm measuring an electron's position with light. I agree that $$\Delta p = h/\lambda$$, where $$\lambda$$ is the wavelength of light that I use. But how does that lead to the HUP? one year ago one year ago

1. vf321

experimentX's link did the job. http://spiff.rit.edu/classes/phys314/lectures/heis/heis.html