## vf321 2 years ago Why is $$\Delta q = \lambda$$? Let's say I'm measuring an electron's position with light. I agree that $$\Delta p = h/\lambda$$, where $$\lambda$$ is the wavelength of light that I use. But how does that lead to the HUP?

1. vf321

experimentX's link did the job. http://spiff.rit.edu/classes/phys314/lectures/heis/heis.html

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