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devibabyy66

  • 3 years ago

Justin is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC. Which of these could be a step to prove that BC2= BA2 + CA2?

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  1. devibabyy66
    • 3 years ago
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    Segment AD : segment CD = segment BD : segment AD, since triangle ADB is similar to triangle CDA. Segment BD : segment BA = segment BA : segment CA, since triangle ADB is similar to triangle CDA. Segment BC : segment BA = segment BA : segment BD, since triangle BCA is similar to triangle BAD. Segment BA : segment DA = segment AC : segment BA, since triangle BCA is similar to triangle BAD.

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  2. cwrw238
    • 3 years ago
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    hint - wo similar triangles are BCA and BAD

  3. devibabyy66
    • 3 years ago
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    is it D?

  4. cwrw238
    • 3 years ago
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    hmm ill check

  5. cwrw238
    • 3 years ago
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    yes - remember the corresponding sides are opposite the equal angles

  6. devibabyy66
    • 3 years ago
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    thank you thank you!!

  7. cwrw238
    • 3 years ago
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    yw

  8. jim_thompson5910
    • 3 years ago
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    I think it's A (not sure 100%), here's why Notice how AD are the first two points in ADB while CD are the first two points in CDA. Keep this relationship/pattern in mind. This is the left side of the equation in part A, which is Segment AD : segment CD The right side is segment BD : segment AD Notice how BD and AD correspond to the same parts of ADB and CDA (you start with the last letter and you read backwards) So this is why I think Segment AD : segment CD = segment BD : segment AD, since triangle ADB is similar to triangle CDA. is true

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