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Justin is using the figure shown below to prove Pythagorean Theorem using triangle similarity.
In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.
Which of these could be a step to prove that BC2= BA2 + CA2?
 one year ago
 one year ago
Justin is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC. Which of these could be a step to prove that BC2= BA2 + CA2?
 one year ago
 one year ago

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devibabyy66Best ResponseYou've already chosen the best response.0
Segment AD : segment CD = segment BD : segment AD, since triangle ADB is similar to triangle CDA. Segment BD : segment BA = segment BA : segment CA, since triangle ADB is similar to triangle CDA. Segment BC : segment BA = segment BA : segment BD, since triangle BCA is similar to triangle BAD. Segment BA : segment DA = segment AC : segment BA, since triangle BCA is similar to triangle BAD.
 one year ago

cwrw238Best ResponseYou've already chosen the best response.2
hint  wo similar triangles are BCA and BAD
 one year ago

cwrw238Best ResponseYou've already chosen the best response.2
yes  remember the corresponding sides are opposite the equal angles
 one year ago

devibabyy66Best ResponseYou've already chosen the best response.0
thank you thank you!!
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
I think it's A (not sure 100%), here's why Notice how AD are the first two points in ADB while CD are the first two points in CDA. Keep this relationship/pattern in mind. This is the left side of the equation in part A, which is Segment AD : segment CD The right side is segment BD : segment AD Notice how BD and AD correspond to the same parts of ADB and CDA (you start with the last letter and you read backwards) So this is why I think Segment AD : segment CD = segment BD : segment AD, since triangle ADB is similar to triangle CDA. is true
 one year ago
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