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devibabyy66
 3 years ago
Justin is using the figure shown below to prove Pythagorean Theorem using triangle similarity.
In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.
Which of these could be a step to prove that BC2= BA2 + CA2?
devibabyy66
 3 years ago
Justin is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC. Which of these could be a step to prove that BC2= BA2 + CA2?

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devibabyy66
 3 years ago
Best ResponseYou've already chosen the best response.0Segment AD : segment CD = segment BD : segment AD, since triangle ADB is similar to triangle CDA. Segment BD : segment BA = segment BA : segment CA, since triangle ADB is similar to triangle CDA. Segment BC : segment BA = segment BA : segment BD, since triangle BCA is similar to triangle BAD. Segment BA : segment DA = segment AC : segment BA, since triangle BCA is similar to triangle BAD.

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.2hint  wo similar triangles are BCA and BAD

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.2yes  remember the corresponding sides are opposite the equal angles

devibabyy66
 3 years ago
Best ResponseYou've already chosen the best response.0thank you thank you!!

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0I think it's A (not sure 100%), here's why Notice how AD are the first two points in ADB while CD are the first two points in CDA. Keep this relationship/pattern in mind. This is the left side of the equation in part A, which is Segment AD : segment CD The right side is segment BD : segment AD Notice how BD and AD correspond to the same parts of ADB and CDA (you start with the last letter and you read backwards) So this is why I think Segment AD : segment CD = segment BD : segment AD, since triangle ADB is similar to triangle CDA. is true
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