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Use separation of variables to solve differential equation: dy/dt=t/((y+1)^1/2)), y(1)=3 ???

  • one year ago
  • one year ago

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  1. dumbcow
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    use algebra to get "t" terms with dt on one side, and "y" terms with dy on other side you might try cross-multiplying here

    • one year ago
  2. S
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    thanks, I know that step, right now I am stuck with interval part

    • one year ago
  3. Algebraic!
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    interval integral?

    • one year ago
  4. S
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    correct, sorry

    • one year ago
  5. dumbcow
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    oh ok, you didn't say so i thought i'd start from beginning :) im guessing the sqrt(y+1) part

    • one year ago
  6. Algebraic!
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    if you can't do the 'y' part in your head... use u=y+1 du =dy \[{ \int\limits_{}^{}} \sqrt{u} du =?\]

    • one year ago
  7. dumbcow
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    sqrt is 1/2 power ... just use power rule

    • one year ago
  8. S
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    so I get 1/2(y+1)^-1/2=t^2/2 ?

    • one year ago
  9. Algebraic!
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    \[\int\limits_{ }^{ } x ^{n} = \frac{ 1 }{ n+1 } * x ^{n+1}\]

    • one year ago
  10. Algebraic!
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    n here = 1/2

    • one year ago
  11. S
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    i got 2/3(Y+1)^3/2=t^2/2, right?

    • one year ago
  12. dumbcow
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    yes ... but don't forget constant "+C" on right side

    • one year ago
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